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anonymous

  • one year ago

(cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2

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  1. anonymous
    • one year ago
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    i am pretty sure it is sin^2

  2. anonymous
    • one year ago
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    bu ti just need another opinion

  3. anonymous
    • one year ago
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    ?

  4. LynFran
    • one year ago
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    (cos theta - cos theta)^2= 0^2 (cos theta + cos theta )^2 = (2cos theta)^2

  5. anonymous
    • one year ago
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    no, you just put that one..... and i said "?"

  6. Mertsj
    • one year ago
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    \[(\cos \theta+\cos \theta)^2=\cos ^2\theta+2\cos ^2\theta+\cos ^2\theta=4\cos ^2 \theta\]

  7. anonymous
    • one year ago
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    so what type of cos equations would equal sin?

  8. anonymous
    • one year ago
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    and he is gone... ignore that last question...

  9. anonymous
    • one year ago
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    wish i i knew how to give medals...

  10. LynFran
    • one year ago
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    yes (2cos theta)^2 = 4 cos ^2 theta

  11. LynFran
    • one year ago
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    we have the Pythagorean identity cos^2 + sin ^2 =1 where cos^2 theta =1- sin^ theta

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