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anonymous
 one year ago
One solution to a quadratic equation is x equals start fraction negative nine plus 21 i over three end fraction full stop What is the solution in simplified standard form, x = a + bi, if a and b are real numbers? Help please
anonymous
 one year ago
One solution to a quadratic equation is x equals start fraction negative nine plus 21 i over three end fraction full stop What is the solution in simplified standard form, x = a + bi, if a and b are real numbers? Help please

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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{9+21i}{3}=\frac{9}{3}+\frac{21i}{3}=3+7i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you bunches. :) Can you help me with 2 more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The complex solution to a quadratic equation is x equals start fraction negative four plus or minus square root of negative 80 end square root over four end fraction full stop Write this solution in standard form, x = a ± bi, where a and b are real numbers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x=\frac{4\pm\sqrt{80}}{4}\]?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok we look for the largest perfect square that is a factor of 80 i get 16 because \(80=16\times 5\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay that makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0therefore \[\sqrt{80}=\sqrt{16\times 5\times (1)}=4\sqrt{5}i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0woah you lost me D: lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i guess i skipped a step \[\sqrt{16\times 5\times (1)}=\sqrt{16}\sqrt{5}\sqrt{1}=4\sqrt{5}i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since \(\sqrt{16}=4\) and \(\sqrt{1}\) gets written as \(i\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is why we were looking for the largest perfect square that is a factor of 80

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let me know when we can continue, it is not over yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay that makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that was the hard part though now we have \[\frac{4\pm4\sqrt{5}i}{4}\]divide each part of the numerator by \(4\) and you are done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is what you have to do for all of them write the radical in simplest radical form for example since \(25\times2=50\) you would have \[\sqrt{50}=5\sqrt{2}i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The number root of order five of ninety one to the power of four end power can be written as ninety one to the power of start fraction cap a over cap b end fraction end power. What is the value of A?
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