A village fair offers three throws for $1 and seven throws for $2. If with 187 throws $57 is made, how many people bought three throws

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A village fair offers three throws for $1 and seven throws for $2. If with 187 throws $57 is made, how many people bought three throws

Mathematics
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we need a variable for either the $1 throws or the $2 throws so we can solve this for one of them which one do you pick and what variable?
could it be x and y
you want to use two variables that is find also unnecessary but fine

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ok that was wrong how can 187 throws bring in only $57?
oooh i got that totally wrong doh sorry
if you only use one variable how would that turn out
lets see if we can do it this way first
the total is 187 so \[x+y=187\]
and also \[\frac{x}{3}+\frac{2y}{7}=57\]
you can solve that for \(x\) and \(y\) probably easier to multiply the second equation by 21 and start with \[x+y=87\\ 7x+6y=1179\]
i get \(x=657\) but that is the number of throw, not the number of people the number of people would be one third of that, since they got three throws each
it says the number of people is suppose to be 25
really? guess i screwed that one up
let me see if i can unscrew it if x is the number of people with 3 throws and y with 7 then maybe we should have \[3x+7y=187\]
and also \[x+2y=57\]
seems to work nicely, get \(x=25,y=16\)

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