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A star in the sky is observed from earth to describe an elliptical path whose minor axis subtends an angle of 36". What angle does the star make with the ecliptic?
I have no idea how to measure angles in anything other than radians or degrees what are these 36''
also I don't even know what eccentricity of an ellipse is, so good luck
|dw:1442805866424:dw| oh man this connection loss, can't evens et it up
36" = 36 arc seconds it means 0.01 degrees
blue is earth
hmmm it looks related to the dot product of your planet's velocity vector and the star's light velocity vector
Yeah sort of, it has to do with relative velocity, but I guess I have to set it up differently, I have a few ideas
Alright so what's the elliptic?
Do you mean ecliptic :P
I don't know, sure why not, I just don't know what you're trying to do or what you're given.
The best way to think of the ecliptic is the ecliptic plane, which is the orbit of earth, I'll try to explain it with a drawing |dw:1442806486190:dw|
Yeah don't worry about it actually, I'll figure it out haha
LIke in my mind, the "abberation" of the star will be at a minimum since you will have stopped approaching and star to move away from it. So it will appear to blue shift then red shift ever-so-slightly at the angle you are looking for.
But I don't actually know any physics so that's just me blowing hot air
Haha, that's actually right, but this question is a bit weird, it's not as complicated, but that was one idea I have, to set it up with the star at rest and in motion and find the angle
|dw:1442806619945:dw| dot product = 0 but not sure if I am applying my idea of circles to ellipses in some way that doesn't exactly transfer over appropriately.
Ok the best way to explain stellar aberration is, as we observe the position of stars, there is a change in light relative velocity
I'll figure it out, thanks yo, but something cool, this is what was used to state that "ether" exists