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## a1234 one year ago Θ is an angle in quadrant 4 in which secΘ = 4. Use a trig identity to find the exact value of tanΘ. I used 1 + tan^2Θ = sec^2Θ. I got tan^2Θ = 15, but since tan is in quad 4, I think tanΘ = -sqrt15. Is this right?

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1. a1234

@jim_thompson5910

2. jim_thompson5910

$\Large \tan(\theta) = -\sqrt{15}$ is correct

3. triciaal

|dw:1442806948688:dw|

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