zuha
  • zuha
A circle has a center at (8,2). The point (3,7) is on the circle. What is the area of the circle to the nearest tenth of a square unit?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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triciaal
  • triciaal
|dw:1442806632519:dw||dw:1442806745433:dw|
zuha
  • zuha
o.o
Jhannybean
  • Jhannybean
|dw:1442806834199:dw|

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More answers

zuha
  • zuha
sqrt(8+3)^2 +(2-7)^2
zuha
  • zuha
-*
Jhannybean
  • Jhannybean
\[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d= \sqrt{(8-3)^2+(2-7)^2} \\ d= \sqrt{(5)^2+(5)^2} \\ d=~?\]
zuha
  • zuha
sqrt25+25 ?
Jhannybean
  • Jhannybean
no decimals please.
Jhannybean
  • Jhannybean
Yes and what is 25 + 25?
zuha
  • zuha
50
Jhannybean
  • Jhannybean
Yes, so \(r=\sqrt{50}\)
Jhannybean
  • Jhannybean
\[\large A_{\text{circle}} = \pi r^2 = \pi (\sqrt{50})^2 = ~?\]
zuha
  • zuha
7
Jhannybean
  • Jhannybean
7?
zuha
  • zuha
sqrt50 =7?
Jhannybean
  • Jhannybean
Okay, yeah I see what you mean
zuha
  • zuha
OOOHHHHH I was putting 50 instead of 7! ;v; Thanks!!
Jhannybean
  • Jhannybean
Typo.
zuha
  • zuha
3.14*7^2=157.1 which is the right answer
zuha
  • zuha
May I ask you another question?
Jhannybean
  • Jhannybean
Well when we square a square root we get the stuff inside the square root :c \[(\sqrt{x})^2 = x\] the square root and the square cancel eachother out. So.... I'm not sure where to go from that point.
Jhannybean
  • Jhannybean
Oh I guess you first simplified \(\sqrt{50} \approx 7.0\) then squared it.
zuha
  • zuha
Yup, may I ask another q?
Jhannybean
  • Jhannybean
I've got to head off OpenStudy right now, but @triciaal can help you! they are very smart as well :) Good luck!
zuha
  • zuha
triciaal
  • triciaal
this is like going the other way you have r from the area then use the formula I gave above for the circle to find (x, y) you are given (h,k) the center
zuha
  • zuha
Yes, thank you for the formula, but I can't really read all of the text you gave before .-.
triciaal
  • triciaal
|dw:1442808097127:dw|
zuha
  • zuha
25?
triciaal
  • triciaal
|dw:1442808182815:dw|
triciaal
  • triciaal
leave as r^2
zuha
  • zuha
What are h and k?
triciaal
  • triciaal
|dw:1442808245627:dw|
triciaal
  • triciaal
coordinates for center of circle
zuha
  • zuha
Rrriiigghhttt.
triciaal
  • triciaal
|dw:1442808479367:dw|
zuha
  • zuha
I'm sorry, I really can't understand...
zuha
  • zuha
@triciaal ?
triciaal
  • triciaal
I don't know how to make you understand I am totally confused now because this is even shown in the diagram I don't know what question you have
zuha
  • zuha
I have four answer options
zuha
  • zuha
(-6, 4) (2, -1) (-4, -4) (2, -9)
zuha
  • zuha
The answer is (2, -1)
zuha
  • zuha
@triciaal ?
triciaal
  • triciaal
that works
zuha
  • zuha
Yes, but how?
zuha
  • zuha
??

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