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zuha

  • one year ago

A circle has a center at (8,2). The point (3,7) is on the circle. What is the area of the circle to the nearest tenth of a square unit?

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  1. triciaal
    • one year ago
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    |dw:1442806632519:dw||dw:1442806745433:dw|

  2. Zuha
    • one year ago
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    o.o

  3. Jhannybean
    • one year ago
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    |dw:1442806834199:dw|

  4. Zuha
    • one year ago
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    sqrt(8+3)^2 +(2-7)^2

  5. Zuha
    • one year ago
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    -*

  6. Jhannybean
    • one year ago
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    \[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d= \sqrt{(8-3)^2+(2-7)^2} \\ d= \sqrt{(5)^2+(5)^2} \\ d=~?\]

  7. Zuha
    • one year ago
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    sqrt25+25 ?

  8. Jhannybean
    • one year ago
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    no decimals please.

  9. Jhannybean
    • one year ago
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    Yes and what is 25 + 25?

  10. Zuha
    • one year ago
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    50

  11. Jhannybean
    • one year ago
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    Yes, so \(r=\sqrt{50}\)

  12. Jhannybean
    • one year ago
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    \[\large A_{\text{circle}} = \pi r^2 = \pi (\sqrt{50})^2 = ~?\]

  13. Zuha
    • one year ago
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    7

  14. Jhannybean
    • one year ago
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    7?

  15. Zuha
    • one year ago
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    sqrt50 =7?

  16. Jhannybean
    • one year ago
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    Okay, yeah I see what you mean

  17. Zuha
    • one year ago
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    OOOHHHHH I was putting 50 instead of 7! ;v; Thanks!!

  18. Jhannybean
    • one year ago
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    Typo.

  19. Zuha
    • one year ago
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    3.14*7^2=157.1 which is the right answer

  20. Zuha
    • one year ago
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    May I ask you another question?

  21. Jhannybean
    • one year ago
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    Well when we square a square root we get the stuff inside the square root :c \[(\sqrt{x})^2 = x\] the square root and the square cancel eachother out. So.... I'm not sure where to go from that point.

  22. Jhannybean
    • one year ago
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    Oh I guess you first simplified \(\sqrt{50} \approx 7.0\) then squared it.

  23. Zuha
    • one year ago
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    Yup, may I ask another q?

  24. Jhannybean
    • one year ago
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    I've got to head off OpenStudy right now, but @triciaal can help you! they are very smart as well :) Good luck!

  25. Zuha
    • one year ago
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    @triciaal

  26. triciaal
    • one year ago
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    this is like going the other way you have r from the area then use the formula I gave above for the circle to find (x, y) you are given (h,k) the center

  27. Zuha
    • one year ago
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    Yes, thank you for the formula, but I can't really read all of the text you gave before .-.

  28. triciaal
    • one year ago
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    |dw:1442808097127:dw|

  29. Zuha
    • one year ago
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    25?

  30. triciaal
    • one year ago
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    |dw:1442808182815:dw|

  31. triciaal
    • one year ago
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    leave as r^2

  32. Zuha
    • one year ago
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    What are h and k?

  33. triciaal
    • one year ago
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    |dw:1442808245627:dw|

  34. triciaal
    • one year ago
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    coordinates for center of circle

  35. Zuha
    • one year ago
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    Rrriiigghhttt.

  36. triciaal
    • one year ago
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    |dw:1442808479367:dw|

  37. Zuha
    • one year ago
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    I'm sorry, I really can't understand...

  38. Zuha
    • one year ago
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    @triciaal ?

  39. triciaal
    • one year ago
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    I don't know how to make you understand I am totally confused now because this is even shown in the diagram I don't know what question you have

  40. Zuha
    • one year ago
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    I have four answer options

  41. Zuha
    • one year ago
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    (-6, 4) (2, -1) (-4, -4) (2, -9)

  42. Zuha
    • one year ago
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    The answer is (2, -1)

  43. Zuha
    • one year ago
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    @triciaal ?

  44. triciaal
    • one year ago
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    that works

  45. Zuha
    • one year ago
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    Yes, but how?

  46. Zuha
    • one year ago
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    ??

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