DF001
  • DF001
Help with algebra: 3/^3rad2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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DF001
  • DF001
\[\frac{ 3 }{ \sqrt[3]{2} }\]
DF001
  • DF001
For one of the rule, the denominator can not be radical but, how can I get rid of that?
DF001
  • DF001
I have to simplify this problem

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DF001
  • DF001
may i ask if the denominator is (2)^1/9
anonymous
  • anonymous
ups my bad, its 2/3
DF001
  • DF001
i can see it now, it's the ^n(radA^m) property
anonymous
  • anonymous
|dw:1442814606283:dw|
DF001
  • DF001
in converting (2)^2/3, what is used is one of the exponential properties, am I correct?
anonymous
  • anonymous
|dw:1442814720626:dw|
anonymous
  • anonymous
yes
DF001
  • DF001
|dw:1442814768602:dw|
DF001
  • DF001
I got a different answer on Mathway and it is 3^3rad2/2
DF001
  • DF001
|dw:1442814815877:dw|
anonymous
  • anonymous
so going back.|dw:1442814759487:dw|
anonymous
  • anonymous
Ignore the other pictures from before, made a mistake on these.
DF001
  • DF001
How can I get |dw:1442814937004:dw|
DF001
  • DF001
I get the part up to the latest picture u sent me but, the answer I got from mathway is weird
anonymous
  • anonymous
|dw:1442814933276:dw|
anonymous
  • anonymous
you do the same process again with the cube root of 4
DF001
  • DF001
Im confused with the process now. i usually multiple the denominator to the numerator but, this question is the very first that i've ever done :/
anonymous
  • anonymous
|dw:1442815066254:dw|
DF001
  • DF001
no matter how i multiple the denominator by itself, it's still a radical :(
anonymous
  • anonymous
you teacher wants you to get rid of the root being on the denominator. The way to cancel it is by multiplying it by itself again such as this.|dw:1442815238734:dw|
DF001
  • DF001
yes, I did it that way but, the denominator came out to be ^3rad
anonymous
  • anonymous
Well we now have the cube root of 4, we have to do the same process once again until be can simplify it off and not have a root on the denominator.
anonymous
  • anonymous
|dw:1442815330274:dw|
anonymous
  • anonymous
|dw:1442815374173:dw|
anonymous
  • anonymous
|dw:1442815438983:dw|
DF001
  • DF001
How can I simplify it by 2
DF001
  • DF001
I can see that rad8 would be 2rad2 if there isn't a 3 as the index
anonymous
  • anonymous
ow just noticed I went on a circle.. my bad lol
anonymous
  • anonymous
|dw:1442815657071:dw|
anonymous
  • anonymous
Forgot to do that on the denominator otherwise you go back to the 3/(2)^(1/3)
DF001
  • DF001
I think I get it alot better now
DF001
  • DF001
I can see that rad4 is simplified to 2x2
anonymous
  • anonymous
|dw:1442815852580:dw|
DF001
  • DF001
could I ask why the denominator turned to 2 when its 2x2x2
DF001
  • DF001
|dw:1442815914490:dw|
DF001
  • DF001
im only confused on that part
DF001
  • DF001
i was wondering what happened to the index 3
anonymous
  • anonymous
|dw:1442815923532:dw|
anonymous
  • anonymous
|dw:1442816056423:dw|
anonymous
  • anonymous
when you square root something, for example 4 then it is equals to 2 because 2*2 = 4 right?
DF001
  • DF001
oh I see now, 2^3=8 thus, the denom is 2
anonymous
  • anonymous
In this case is cube too meaning you need the same number 3 times and multiply it to get the answer. In this case 8 would be 2*2*2 = 8
DF001
  • DF001
I understand now, thank you very much :)
anonymous
  • anonymous
Cube root*
anonymous
  • anonymous
Sure, no problem :)

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