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anonymous
 one year ago
PLEASE HELP!!!
Let $ABCD$ be a cyclic quadrilateral. Let $P$ be the intersection of $\overline{AD}$ and $\overline{BC}$, and let $Q$ be the intersection of $\overline{AB}$ and $\overline{CD}$. Prove that the angle bisectors of $\angle DPC$ and $\angle AQD$ are perpendicular.
anonymous
 one year ago
PLEASE HELP!!! Let $ABCD$ be a cyclic quadrilateral. Let $P$ be the intersection of $\overline{AD}$ and $\overline{BC}$, and let $Q$ be the intersection of $\overline{AB}$ and $\overline{CD}$. Prove that the angle bisectors of $\angle DPC$ and $\angle AQD$ are perpendicular.

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0Let \(ABCD\) be a cyclic quadrilateral. Let \(P\) be the intersection of \(\overline{AD}\) and \(\overline{BC}\), and let \(Q\) be the intersection of \(\overline{AB}\) and \(\overline{CD}\). Prove that the angle bisectors of \(\angle DPC\) and \(\angle AQD\) are perpendicular. question

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0you must be knowing that opposite angles in a cyclic quadrilateral add up to 180

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0As a start, use that to show that \(\angle DAB \cong \angle BCQ\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i see where you're going! thanks so much! I'll try it out myself first and come back if i need more help!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0** 1) By triangle exterior angle theorem, \(\angle DAB\cong \angle P + \angle B\). 2) Since the opposite angles in a cyclic quadrilateral add up to \(180\) : \(\angle DAB\cong \angle BCQ\) 3) From above two steps, we get \(\angle BQC \cong 180(\angle P+\angle B)  \angle B\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I'll let you finish it off.. good luck!

phi
 one year ago
Best ResponseYou've already chosen the best response.0for what it is worth, here is a complicated approach
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