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anonymous

  • one year ago

Please help with this pre-cal questions in the attachment.

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  1. anonymous
    • one year ago
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  2. ***[ISURU]***
    • one year ago
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    do u know the meaning of using [ ] or () brackets ?

  3. anonymous
    • one year ago
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    Yes

  4. ***[ISURU]***
    • one year ago
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    well ... then ur 1st Question ask for a function ( which i will denote by f(x) ) which should be greater than or equal to 0 but lesser than + infinity ..... usually functions with square roots belongs to this type

  5. ***[ISURU]***
    • one year ago
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    \[f(x) = \sqrt{x}\] this is a very simple example

  6. ***[ISURU]***
    • one year ago
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    u cant find the square root of \[\sqrt{-3}\] or any other negative number.... got it ?

  7. anonymous
    • one year ago
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    Okay, got it.

  8. ***[ISURU]***
    • one year ago
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    the second one says... a function which is greater than - infinity and lesser than + infinity... usually ...almost any linear function satisfy this

  9. ***[ISURU]***
    • one year ago
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    \[f(x) = x + 8 \]\[f(x) = 5x + 10 \]....like any u like...

  10. anonymous
    • one year ago
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    Oh okay

  11. ***[ISURU]***
    • one year ago
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    these functions can take either negative or positive values... no harm happens :)

  12. anonymous
    • one year ago
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    Okay cool

  13. ***[ISURU]***
    • one year ago
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    now for the last one... its the same as the second one ..but it cant be equal to zero...usually a function with this range means that the function is a fraction ...like the below one

  14. ***[ISURU]***
    • one year ago
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    \[f(x) = \frac{ 5x + 8 }{ x}\]

  15. ***[ISURU]***
    • one year ago
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    if u substitute 0 in the above one...u wont be able to tell what will be the answer... because a number divide by zero could be either + infinity or - infinity

  16. anonymous
    • one year ago
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    Right, ok, got it.

  17. anonymous
    • one year ago
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    :)

  18. ***[ISURU]***
    • one year ago
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    soo... in a fraction the denominator cant be zero... any function with a fraction where the denominator will be 0 when x is 0 will be ur answer for the third and last of ur first question :)

  19. ***[ISURU]***
    • one year ago
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    now... do u want help in the 2nd one too ?

  20. anonymous
    • one year ago
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    Yes please. Thank you for helping me with the first question! :)

  21. ***[ISURU]***
    • one year ago
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    u r welcome :) lets c... the 2nd one

  22. ***[ISURU]***
    • one year ago
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    they say the original price is "x" and the price after you apply the coupon is f(x) ...... what happens when u applied the coupon is.... the cut off 25 dollars ..... so if the price of ur dress is "x" ...after u apply the coupon ..the price is " x -25 " ...because they cut off 25$

  23. ***[ISURU]***
    • one year ago
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    so... f(X) = X -25 ...got it ?

  24. anonymous
    • one year ago
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    Okay I understand that

  25. ***[ISURU]***
    • one year ago
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    now lets consider g(x) ..... g(x) is the price of dress withe the 20% discount applied.... a 20% discount means that u can buy the dress less than 20% of the original price if the original price is "x" then 20% of "x" is (20/100)x then g(x) = x - (20/100)x got it ?

  26. anonymous
    • one year ago
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    Yes that makes sense

  27. ***[ISURU]***
    • one year ago
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    and finally .... ( f o g )(x) means f( g (x) )...where u have to substituent g(x) instead of "x" in f(x) therefor (f o g)(x) = g(x) - 25 = x - (20/100)x - 25

  28. ***[ISURU]***
    • one year ago
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    in the same way (g o f)(x) means g ( f(x) ) where u have to substitute "f(x)" instead of "x" in "g(x)" therefor (g o f)(x) = f(x) - (20/100)f(x) = x - 25 - [ (20/100)( x -25) ]

  29. ***[ISURU]***
    • one year ago
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    i hope u understand it :)

  30. anonymous
    • one year ago
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    Those two I was really confused on, but I understand them now :)

  31. anonymous
    • one year ago
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    Thank you sooo much!! I really appreciate it! :)

  32. ***[ISURU]***
    • one year ago
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    u r welcome :)

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