kosonge
  • kosonge
Indicate which property is illustrated in Step 2. Step 1 8 + (5 + 8) + 0 = 8 + (8 + 5) + 0 Step 2 = (8 + 8) + (5 + 0) Step 3 = (8 + 8) + 5 Step 4 = 16 + 5 commutative property of addition identity property of addition associative property of addition distributive property
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Hi, I can help you with this. They're asking what was used in going from 8 + (8 + 5) + 0 (*) to (8+8) + (5 + 0) (**) First question: did the ORDER the #s are listed change in going from (*) to (**)?
kosonge
  • kosonge
no just different ()'s
anonymous
  • anonymous
Here's what I mean: In (*), the numbers (listed from left to right) are: 8, 8, 5, 0 In (**), they are: 8, 8, 5, 0 Did the order change? Did any #s change places?

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kosonge
  • kosonge
no
anonymous
  • anonymous
Good. So, it's not a commutative law, because "commuting" has to do with "changing places". Now, did the GROUPING of the #s change? LIke, in 8 + (8+5) + 0, the 8 and the 5 are grouped together...
anonymous
  • anonymous
By the way, the page below has memory devices for "commutative" versus "associative" which might be helpful for you: http://www.onemathematicalcat.org/algebra_book/online_problems/addition.htm
anonymous
  • anonymous
Are you still there? Do you need a hint?
anonymous
  • anonymous
OK, guess you're gone ... hope you figured it out. Have a great day!

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