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anonymous
 one year ago
Given that c (ax + by  cz) = b (ax  by + cz) = a ( ax + by + cz) = 2
then ax + by + cz/ab + bc + ca = ?
anonymous
 one year ago
Given that c (ax + by  cz) = b (ax  by + cz) = a ( ax + by + cz) = 2 then ax + by + cz/ab + bc + ca = ?

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perl
 one year ago
Best ResponseYou've already chosen the best response.1Let's unpack the first statement. c (ax + by  cz) = b (ax  by + cz) = a ( ax + by + cz) = 2

perl
 one year ago
Best ResponseYou've already chosen the best response.1If we look at the first two statements c (ax + by  cz) = 2 b (ax  by + cz) = 2 It follows that (ax + by  cz) = 2/c (ax  by + cz) = 2/b now you can add these two equations to eliminate variables x and y 2ax = 2/c + 2/b

perl
 one year ago
Best ResponseYou've already chosen the best response.1can you solve that for x ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. How do we exactly approach such questions? Is there any trick?

perl
 one year ago
Best ResponseYou've already chosen the best response.1What I wrote is clear so far?

perl
 one year ago
Best ResponseYou've already chosen the best response.1The approach I used is common to solving linear equations, try to find a way to eliminate a variable. Well not exactly this approach, after some work

perl
 one year ago
Best ResponseYou've already chosen the best response.1lets be more careful with solving for x

perl
 one year ago
Best ResponseYou've already chosen the best response.12ax = 2/c + 2/b you divided out 2 correctly ax = 1/c + 1/b first simplify 1/c + 1/b ax = ( b + c ) / (bc) now divide by a x = ( b + c ) / (abc)

perl
 one year ago
Best ResponseYou've already chosen the best response.1$$ \large \frac{1}{b} + \frac{1}{c} = \frac{1}{b}\cdot \frac {c}{c} + \frac{1}{c} \cdot \frac{b}{b}= \frac{c}{bc} + \frac{b}{bc} = \frac{b+c}{bc}$$
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