MEDAL AND FAN PROMISED!!! PLZ HELP!!!

- anonymous

MEDAL AND FAN PROMISED!!! PLZ HELP!!!

- schrodinger

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- anonymous

f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3

- anonymous

can you help me find the rate of change @kiamousekia

- idku

\(\large\color{black}{f(x)=2(3)^x}\)
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- anonymous

yes

- anonymous

\i need to find the rage of change

- anonymous

with that formula

- anonymous

@kiamousekia can u help me plz

- idku

How would you normally find the slope between the slope between points
\(\large\color{black}{(a,b)}\) and \(\large\color{black}{(c,d)}\) ?
\(\large\color{black}{m=\dfrac{b-d}{a-c}}\)

- idku

For section A, you need to find f(0) and f(1),
and then the slope between (0,f(0)) and (1,f(1)).

- anonymous

well i need 2 Find the average rate of change of each section.

- anonymous

so ik that formula

- anonymous

but i need help doing it

- idku

ok, and tell me what is f(0)=? and f(1)=?

- anonymous

(0,1)?

- idku

\(\large\color{black}{f(x)=2(3)^x}\)
\(\large\color{black}{f(0)=2(3)^0=?}\)
\(\large\color{black}{f(1)=2(3)^1=?}\)

- idku

(anything raised to power 0, is 1)

- anonymous

so i need 2 answer that equasion

- anonymous

Idk sorry

- idku

yes, you need to answer my 2 last questions
(those are your y-values of the 2 points, respectively)
and then use the slope formula

- anonymous

f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3
this is what im asking tho i need to find them sepretly

- idku

I know.

- idku

You have to know the y-coordinates of the 2 points to find the slope, don't you?

- anonymous

ok ok i got it now

- idku

What is the y-coordinate when x=0?
What is the y-coordinate when x=1?

- idku

(recall that your function is \(\large\color{black}{f(x)=2(3)^x}\) )

- idku

plug in 0 for x, and then plug in 1 for x.

- anonymous

so its 6 and there are no soulutions 2 the first 1

- idku

\(\large\color{black}{f(x)=2(3)^x}\)
\(\large\color{black}{f(0)=2(3)^0=2\cdot1=2}\)
So the y-coordinate when x=0, is y=2

- idku

Can you find the y-value when x=1? (do it same way I have done it)

- anonymous

im so confused

- idku

and im so sorry

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