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catscatscats

  • one year ago

The period of function f(x) = sec(x/4) is

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  1. catscatscats
    • one year ago
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    2Π radians Π radians 4Π radians 8Π radians

  2. amistre64
    • one year ago
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    what is the period normally associated with the sec function?

  3. catscatscats
    • one year ago
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    2pi

  4. amistre64
    • one year ago
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    then all we need to do is solve for x when: x/4 = 2pi

  5. catscatscats
    • one year ago
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    ummm

  6. amistre64
    • one year ago
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    you can ignore the pi part since all the options have it ... when is x/4 = 2 ?

  7. catscatscats
    • one year ago
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    the answer isn't 2pi

  8. amistre64
    • one year ago
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    when does x/4 = 2?

  9. catscatscats
    • one year ago
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    Idk? that's why im confused?

  10. amistre64
    • one year ago
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    if you are doing trig, then you must have graduated from algebra class ...

  11. amistre64
    • one year ago
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    something, divided by 4, is equal to 2 ...

  12. catscatscats
    • one year ago
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    Ugh yeah but like how does that have to do with the problem

  13. catscatscats
    • one year ago
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    The answer isn't 2pi. I've already tried it

  14. amistre64
    • one year ago
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    sec(2pi) is what we want to go for. sec(x/4) = sec(2pi), when x/4 = 2pi

  15. amistre64
    • one year ago
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    solve for x ...

  16. catscatscats
    • one year ago
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    so 4pi

  17. amistre64
    • one year ago
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    no, 4pi/4 is not 2pi, its pi

  18. catscatscats
    • one year ago
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    8pi.

  19. amistre64
    • one year ago
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    8pi/4 = 2pi ... yes

  20. catscatscats
    • one year ago
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    Thank you. Can you help with some more too please

  21. amistre64
    • one year ago
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    not at the moment, but good luck

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