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Lena772
 one year ago
The anion of a Weak Acid is
A) a strong base
B) a strong acid
C) a weak base
D) a weak acid
E) amphiprotic
F) a spectator ion
Lena772
 one year ago
The anion of a Weak Acid is A) a strong base B) a strong acid C) a weak base D) a weak acid E) amphiprotic F) a spectator ion

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Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Well a weak acid is only partially dissociated, so the anion or conjugate base would be a strong base I think. Remember whenever an acid loses a proton the result is the conjugate base; when a base gains a proton the result is the conjugate acid.

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0Strong base is incorrect. :/ @Photon336

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2Are weak bases. Look at the relationship \(K_w=K_A*K_B\) if we have a weak acid, like HF, with \(K_A=7.2*10^{4}~M\) then we have \(K_B=\dfrac{K_W}{K_A}=\dfrac{1.0*10^{14}M^2}{7.2*10^{4}~M}=1.39*10^{11}~M\) which is a value expected for a weak base.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So @aaronq , doesnt matter if the acid is strong or weak, the conjugated base (the anion of the acid) always will be a weak base? I was also confused by the sentence "the stronger the acid, the weaker the conjugated base" that take me to think that the weakest the acid the strongest the conjugated base as @Photon336 mention. But according to your explanation even the weakest acid will produce a weak conjugated base.

aaronq
 one year ago
Best ResponseYou've already chosen the best response.2Yeah. It'll always be weak (relatively, look up the Kb for strong bases and compare), if it wasn't it would immediately mop up the proton and the substance would not be acidic.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0@aaronq interesting. point. so it has to be weak because if it immediately pulled up the protons it wouldn't be acidic to begin with. very interesting

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@aaronq thank you !!!
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