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anonymous
 one year ago
Simplify the expression four root of order three of x times x to the power of start fraction three over two end fraction end power times y to the power of six end power times y to the power of start fraction one over two end fraction end power and rewrite it in radical form.
anonymous
 one year ago
Simplify the expression four root of order three of x times x to the power of start fraction three over two end fraction end power times y to the power of six end power times y to the power of start fraction one over two end fraction end power and rewrite it in radical form.

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge \sqrt[4]{x^3}\times x^{\frac{3}{2}}\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and \[\huge y^6\times y^{\frac{1}{2}}\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[y^6\times y^{\frac{1}{2}}=y^{6+\frac{1}{2}}=y^{\frac{13}{2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[4\sqrt[3]{x}*x^\frac{ 3 }{ 2 }*y^6*y ^\frac{ 1 }{ 2 }\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[4x^{\frac{1}{3}+\frac{3}{2}}=4x^{\frac{11}{6}}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so \[4\sqrt[6]{x^{11}}\times \sqrt{y^{13}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got \[4\sqrt[11]{x^6} \sqrt[13]{y^2}\]
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