## anonymous one year ago I need help! Will medal and fan with testimonial! No straight up answers please.

1. anonymous

Here is link to problem I need help with http://i.imgur.com/fgRmRoV.png

2. anonymous

pick two points on the line first so we can use that

3. anonymous

Okay what about 4,5 and 2,3

4. anonymous

the line doesn't seem to touch those points though goes close by, but doesn't seem those points are ON the line

5. anonymous

OHH sorry

6. anonymous

2,2 and 4,5?

7. anonymous

same issue, those two points are not ON the line

8. anonymous

Are you sure? I must be blind...

9. anonymous

yes, I have the pictured zoomed in

10. anonymous

5,6 -5,-6?

11. anonymous

those will work well, to get the slope is simple then $$\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad % (c,d) &({\color{red}{ -5}}\quad ,&{\color{blue}{ -6}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}$$

12. anonymous

okay give me a second and i will check answer with you

13. anonymous

It's 0, 0?!?

14. anonymous

well, 0,0 is ON the line, yes is not the slope though

15. anonymous

When I did the formula I got 0, 0. I'm sorry I am really horrible at math...

16. haleyelizabeth2017

Can you show us how you got that?

17. anonymous

0,0? the slope is a value alone, not an ordered pair though

18. anonymous

-10, -12?

19. anonymous

Oh wait I didn't read what you just put.

20. anonymous

0.83 is the slope?

21. anonymous

well $$\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad % (c,d) &({\color{red}{ -5}}\quad ,&{\color{blue}{ -6}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -6}}-{\color{blue}{ 6}}}{{\color{red}{ -5}}-{\color{red}{ 5}}}\implies \cfrac{\cancel{-12}}{\cancel{-10}}\implies \cfrac{6}{5}$$

22. anonymous

23. anonymous

yeap

24. anonymous

:D thank you!