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anonymous

  • one year ago

I need help! Will medal and fan with testimonial! No straight up answers please.

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  1. anonymous
    • one year ago
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    Here is link to problem I need help with http://i.imgur.com/fgRmRoV.png

  2. jdoe0001
    • one year ago
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    pick two points on the line first so we can use that

  3. anonymous
    • one year ago
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    Okay what about 4,5 and 2,3

  4. jdoe0001
    • one year ago
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    the line doesn't seem to touch those points though goes close by, but doesn't seem those points are ON the line

  5. anonymous
    • one year ago
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    OHH sorry

  6. anonymous
    • one year ago
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    2,2 and 4,5?

  7. jdoe0001
    • one year ago
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    same issue, those two points are not ON the line

  8. anonymous
    • one year ago
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    Are you sure? I must be blind...

  9. jdoe0001
    • one year ago
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    yes, I have the pictured zoomed in

  10. anonymous
    • one year ago
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    5,6 -5,-6?

  11. jdoe0001
    • one year ago
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    those will work well, to get the slope is simple then \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad % (c,d) &({\color{red}{ -5}}\quad ,&{\color{blue}{ -6}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

  12. anonymous
    • one year ago
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    okay give me a second and i will check answer with you

  13. anonymous
    • one year ago
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    It's 0, 0?!?

  14. jdoe0001
    • one year ago
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    well, 0,0 is ON the line, yes is not the slope though

  15. anonymous
    • one year ago
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    When I did the formula I got 0, 0. I'm sorry I am really horrible at math...

  16. haleyelizabeth2017
    • one year ago
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    Can you show us how you got that?

  17. jdoe0001
    • one year ago
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    0,0? the slope is a value alone, not an ordered pair though

  18. anonymous
    • one year ago
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    -10, -12?

  19. anonymous
    • one year ago
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    Oh wait I didn't read what you just put.

  20. anonymous
    • one year ago
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    0.83 is the slope?

  21. jdoe0001
    • one year ago
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    well \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad % (c,d) &({\color{red}{ -5}}\quad ,&{\color{blue}{ -6}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -6}}-{\color{blue}{ 6}}}{{\color{red}{ -5}}-{\color{red}{ 5}}}\implies \cfrac{\cancel{-12}}{\cancel{-10}}\implies \cfrac{6}{5}\)

  22. anonymous
    • one year ago
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    6/5 is the answer?

  23. jdoe0001
    • one year ago
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    yeap

  24. anonymous
    • one year ago
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    :D thank you!

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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