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anonymous
 one year ago
I need help! Will medal and fan with testimonial!
No straight up answers please.
anonymous
 one year ago
I need help! Will medal and fan with testimonial! No straight up answers please.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here is link to problem I need help with http://i.imgur.com/fgRmRoV.png

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pick two points on the line first so we can use that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay what about 4,5 and 2,3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the line doesn't seem to touch those points though goes close by, but doesn't seem those points are ON the line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0same issue, those two points are not ON the line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you sure? I must be blind...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, I have the pictured zoomed in

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0those will work well, to get the slope is simple then \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad % (c,d) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay give me a second and i will check answer with you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, 0,0 is ON the line, yes is not the slope though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When I did the formula I got 0, 0. I'm sorry I am really horrible at math...

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Can you show us how you got that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00,0? the slope is a value alone, not an ordered pair though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait I didn't read what you just put.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}})\quad % (c,d) &({\color{red}{ 5}}\quad ,&{\color{blue}{ 6}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ 6}}{\color{blue}{ 6}}}{{\color{red}{ 5}}{\color{red}{ 5}}}\implies \cfrac{\cancel{12}}{\cancel{10}}\implies \cfrac{6}{5}\)
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