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vera_ewing

  • one year ago

Math question

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  1. vera_ewing
    • one year ago
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  2. haleyelizabeth2017
    • one year ago
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    one sec

  3. haleyelizabeth2017
    • one year ago
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    Maybe @jdoe0001 can help...? not sure :)

  4. anonymous
    • one year ago
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    \[\left( f-g \right)\left( x \right)=f \left( x \right)-g \left( x \right)=\frac{ x }{ x-3 }-\left( 2x-1 \right)=?\]

  5. vera_ewing
    • one year ago
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    I got \[\frac{ -2x ^{2}-8x+3 }{ x-3 }\]

  6. anonymous
    • one year ago
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    \[=\frac{ x-\left( x-3 \right)\left( 2x-1 \right) }{ x-1 }=\frac{ x-\left( 2x^2-x-6x+3 \right) }{ x-1 }=?\]

  7. vera_ewing
    • one year ago
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    Why didn't I get one of the answer choices??

  8. anonymous
    • one year ago
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    you can see my calculation it should be -3 ,not +3 in your calculation.

  9. vera_ewing
    • one year ago
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    So now I'm getting -2x + 6 + (3/x-1)

  10. anonymous
    • one year ago
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    you got my calculation.

  11. vera_ewing
    • one year ago
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    Ok what did you get as your final answer?

  12. anonymous
    • one year ago
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    in the denominator correction it is x-3 not x-1

  13. vera_ewing
    • one year ago
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    So is the answer A?

  14. anonymous
    • one year ago
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    yes

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