## anonymous one year ago An object of mass m has an an accleration of magnitude a, when a force of strength F acts on it (on a frictionless surface). Four other objects on the same surface have the following masses and accelerations: A: Mass = 2m, Acceleration = a/2 B: Mass = m, Acceleration = 2a C: Mass = 2m, Acceleration = a D: Mass = 2m, Acceleration = 2a Which of the options below correctly ranks the strengths of the forces acting on these four objects, from weakest to strongest.

1. johnweldon1993

Hint* $$\large F = ma$$

2. anonymous

So all I need to do is multiple the mass and acceleration for all of them? We haven't had this in class yet so I'm not really sure.

3. johnweldon1993

That is correct...And you will be learning about it a lot! Newtons 2nd Law..F = ma So yes just multiply and simplify...what do you get?

4. anonymous

A: 4 B:2 C:2 D:4 Would that be right?

5. anonymous

Because if that's the case how do you decide which one is bigger when B and C are the same values just like A and D?

6. johnweldon1993

Not quite Ex: A) $$\large F = ma$$ $$\large F=2m\times \frac{a}{2} = ma$$ B) $$\large F = ma$$ $$\large F=m\times 2a = 2ma$$ *So that should show you that B would be twice as strong of a force as A right? Continue on from there :)

7. anonymous

Sorry about the super late reply. So it would be A<C<D<B?