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teller
 one year ago
Someone mind checking my work?
The radioactive substance cesium137 has a halflife of 30 years. The amount A(t) (in grams) of a sample of cesium137 remaining after t years is given by the following exponential function.
A(t)=381(1/2)^t/30
Find the initial amount in the sample and the amount remaining after 50 years. Round your answers to the nearest gram as necessary.
initial amount = 381
after 50 years = 1270
teller
 one year ago
Someone mind checking my work? The radioactive substance cesium137 has a halflife of 30 years. The amount A(t) (in grams) of a sample of cesium137 remaining after t years is given by the following exponential function. A(t)=381(1/2)^t/30 Find the initial amount in the sample and the amount remaining after 50 years. Round your answers to the nearest gram as necessary. initial amount = 381 after 50 years = 1270

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you mean? I see no work. A radioactive substance would have less grams after 50 years. In other words, radioactive substances decreases in grams every year.

teller
 one year ago
Best ResponseYou've already chosen the best response.0I sent my work down below where it says initial amount = 381 after 50 years = 1270

teller
 one year ago
Best ResponseYou've already chosen the best response.0I plugged the information into my online calculator and that's what I got after 50 years.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You could at least say you plugged it in. There was no indicator to what you did except put in the answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because I dont think you plugged it right.

teller
 one year ago
Best ResponseYou've already chosen the best response.0A(50)=381(1/2)^50/30 got me 1270

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[381 \times (0.5)^{\frac{ 50 }{ 30 }}\]

teller
 one year ago
Best ResponseYou've already chosen the best response.0But my thing says to use the formula A(t)=381(1/2)^t/30

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Same thing.... (1/2)=0.5

teller
 one year ago
Best ResponseYou've already chosen the best response.0so rounding it would make it 120?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@teller Remember PEMDAS: A(t)=381(1/2)^t/30 equals A(t)=381[(1/2)^t]/30 which is not correct. You need to write A(t)=381(1/2)^(t/30) or else calculators will give wrong numbers. Calculators go strictly with PEMDAS, doesn't know what you want! xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes exactly. I tried figuring out what @teller did wrong, but couldnt figure on how to get 1270.
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