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anonymous
 one year ago
NEED HELP
To which family does the function y=2^x+5 belong
quadratic
square root
exponential
logarithmic
anonymous
 one year ago
NEED HELP To which family does the function y=2^x+5 belong quadratic square root exponential logarithmic

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Same question for the equation y=(x+2)^(1/2)+3 The answers can be quadratic square root exponential reciprocal I know it's not exponential

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\Large y=2^{\color{blue}{ x}}+5\impliedby hint\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I already know what the equation is... I just don't understand how to solve :/

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1we.. you asked to which it belongs to not to solve it

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1seems solved already anyway

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I guess I don't understand completely what the differences are.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\Large y=(x+2)^{\frac{1}{2}+3}?\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well.. can't be... so I assume is hmmm \(\Large y=(x+2)^{\frac{1}{2}}+3?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The +3 is not connected to the exponent

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf y=(x+2)^{\frac{1}{2}}+3\implies y3=(x+2)^{\frac{1}{2}} \\ \quad \\ y3=\sqrt{x+2}\implies (y3)^2=(\sqrt{x+2})^2\implies (y3)^2=x+2 \\ \quad \\ (y3)^22=x\implies y^26y+92=x \\ \quad \\ y^26y+7=x\impliedby quadratic\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! I will write this down in my notes!! :) Is the first one B?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1and yes, both have an exponent, and one could say they're both exponenttials BUT the difference being, one exponent is an rational or fraction the other is not so the rational can always be expressed as a root and from there you end up with some exponent on the other side

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\Large { a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}} \\\quad \\ % rational negative exponent a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}} \implies \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}\qquad\qquad % radical denominator \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}= \cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}} \\\quad \\ }\) thus
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