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airyana1114
 one year ago
Let f(x)=x^216. Find f^1(x).
Can someone check my work?
airyana1114
 one year ago
Let f(x)=x^216. Find f^1(x). Can someone check my work?

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airyana1114
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x)=x^{2}16 \] Step1: Replace f(x) with y. \[y=x ^{2}16\] Step 2: Switch my x and y variables. \[x=y ^{2}16\] Step 3: Add 16 to both sides of the equation. \[x+16=y ^{2}\] Step 4: Take the square root of both sides of the equation. \[\sqrt{x+16}=y\] Step 5: Replace y with f(x). \[\sqrt{x+16}=f ^{1}(x)\] Did I do this right?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Correct indeed :)

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.1Awesome, thank you! @johnweldon1993

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1No problem great work!
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