## airyana1114 one year ago Let f(x)=x^2-16. Find f^-1(x). Can someone check my work?

1. airyana1114

$f(x)=x^{2}-16$ Step1: Replace f(x) with y. $y=x ^{2}-16$ Step 2: Switch my x and y variables. $x=y ^{2}-16$ Step 3: Add 16 to both sides of the equation. $x+16=y ^{2}$ Step 4: Take the square root of both sides of the equation. $\sqrt{x+16}=y$ Step 5: Replace y with f(x). $\sqrt{x+16}=f ^{-1}(x)$ Did I do this right?

2. johnweldon1993

Correct indeed :)

3. airyana1114

Awesome, thank you! @johnweldon1993

4. johnweldon1993

No problem great work!