YumYum247
  • YumYum247
Please help me Astrophysics!!!! :"D
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
YumYum247
  • YumYum247
1 Attachment
YumYum247
  • YumYum247
@sweetburger Please help me!!!! :)
YumYum247
  • YumYum247
Can anyone please help me find the resultant angle?!?!?!?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

YumYum247
  • YumYum247
@MAEMAEHOCKEY final got your tagname :D
anonymous
  • anonymous
give me a couple of mins
YumYum247
  • YumYum247
np, take your time :)
anonymous
  • anonymous
i thought it would be simple
YumYum247
  • YumYum247
and i thought ......nvm. i'll just beg at someone's else's door. -_-
anonymous
  • anonymous
i willl help u i am happy to
YumYum247
  • YumYum247
really?????? :D
anonymous
  • anonymous
yaaa
YumYum247
  • YumYum247
yuss!!!
anonymous
  • anonymous
ok i think i got it
YumYum247
  • YumYum247
Hey don't bother, i don't wanna make you go through stress just for a question...leave it, i'll just ask someone else...Chill...:"D
anonymous
  • anonymous
what .......i am not stressed
YumYum247
  • YumYum247
i'm just saying if your here to be a chill bird, then be a chill bird, i ain't trapping you in a cage. :"D
anonymous
  • anonymous
i am not
YumYum247
  • YumYum247
Aait then.... i just wanna let you know that i've already done 90% of the question, i just need to find the resultant angle. and Thanks!!!
anonymous
  • anonymous
ok i think i got it if i am doing it right
YumYum247
  • YumYum247
please proceed....:D
anonymous
  • anonymous
24 right ???
mathmate
  • mathmate
|dw:1442883489245:dw|
mathmate
  • mathmate
can you confirm if the 24 and 32 degrees as shown in the marked up diagram? |dw:1442883620661:dw|
YumYum247
  • YumYum247
hold up let me attach a picture of the actual question....don't go anywhere...promise me!!! O_O
mathmate
  • mathmate
ok!
YumYum247
  • YumYum247
mathmate
  • mathmate
|dw:1442883835366:dw| Yes, this is a little better, with the force magnitudes. One suggestion I make for your future solutions is to draw the forces in the same orientation as the original. This way, there is a lesser chance of making mistakes.
YumYum247
  • YumYum247
ok :)
mathmate
  • mathmate
|dw:1442883951868:dw| So R^2=15^2+12^2-2(15)(12)cos(124)=23.8812 as you had it.
mathmate
  • mathmate
|dw:1442884257124:dw| sin(\(\theta\)/12=sin(124)/R so sin(\(\theta\)=12 sin(124)/23.8812=0.416582 \(\theta\)= asin(0.416582)=24.619 degrees (measured from the 15N force, or 24.619-24=0.619 degrees from the axis of the direction of the vehicle.
mathmate
  • mathmate
correction: a little confusion for R. Should have written R^2=......., and R=sqrt(...)=23.8812 N
mathmate
  • mathmate
@YumYum247 Still there? To find the angle, I used the sine rule, but forgot to indicate it.
YumYum247
  • YumYum247
yes i'm still here....!!!
YumYum247
  • YumYum247
0.61deg.....but that's not even a one whole degree tho :O
YumYum247
  • YumYum247
so you used... SineA/a = SineC/c SinA/15 = Sin124/24
mathmate
  • mathmate
That's with respect to the axis of the vehicle. |dw:1442885722739:dw|
mathmate
  • mathmate
Yes, but sin(theta)/12 = sin(124)/R. Sine rule sometimes does not give the correct angles when the unknown angle is near 90 degrees (angle or supplement). But here we know the unknown angle is acute, so there's no problem.
YumYum247
  • YumYum247
yah sorry i realized that.... :D
YumYum247
  • YumYum247
Again thank you infinite :"D
mathmate
  • mathmate
You're welcome! :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.