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anonymous
 one year ago
quick algebra question?
anonymous
 one year ago
quick algebra question?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use the graph to determine the equation of the circle in (a) centerradius form and (b) general form. The graph is a circle with points at the top(3,7) the right (1,3) the bottom (3,1) and the left(7,3). Can someone please help with putting it in these forms? TIA

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1So for the circleradius form, you can read it off the graph, so you can see from the circle on the graph that the centre is at (3, 3). also, by having located the centre, you can now see what the radius is too, (just count horizontally or vertically from the centre till you hit the circumference) so radius is 4. The equation of a circle is r^2 = (x{x coordinate of centre})^2 + (y  {y coordinate of centre})^2 note r is radius. So you now want to substitute your radius and coordinates of the centre in, to find the circleradius form

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.1And as for the general form, you want to simplify the equation down and move everything (except the y) to the right hand side, in its simplest form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thanks I'll try again and tag you if I need more help.. @FireKat97

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0figured it out thanks!
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