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anonymous

  • one year ago

quick algebra question?

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  1. anonymous
    • one year ago
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    Use the graph to determine the equation of the circle in (a) center-radius form and (b) general form. The graph is a circle with points at the top(-3,7) the right (1,3) the bottom (-3,-1) and the left(-7,3). Can someone please help with putting it in these forms? TIA

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    @Nnesha

  4. FireKat97
    • one year ago
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    So for the circle-radius form, you can read it off the graph, so you can see from the circle on the graph that the centre is at (-3, 3). also, by having located the centre, you can now see what the radius is too, (just count horizontally or vertically from the centre till you hit the circumference) so radius is 4. The equation of a circle is r^2 = (x-{x coordinate of centre})^2 + (y - {y coordinate of centre})^2 note- r is radius. So you now want to substitute your radius and coordinates of the centre in, to find the circle-radius form

  5. FireKat97
    • one year ago
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    And as for the general form, you want to simplify the equation down and move everything (except the y) to the right hand side, in its simplest form

  6. anonymous
    • one year ago
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    Ok thanks I'll try again and tag you if I need more help.. @FireKat97

  7. FireKat97
    • one year ago
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    no problem :)

  8. anonymous
    • one year ago
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    figured it out thanks!

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