quick algebra question?

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quick algebra question?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Use the graph to determine the equation of the circle in (a) center-radius form and (b) general form. The graph is a circle with points at the top(-3,7) the right (1,3) the bottom (-3,-1) and the left(-7,3). Can someone please help with putting it in these forms? TIA

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So for the circle-radius form, you can read it off the graph, so you can see from the circle on the graph that the centre is at (-3, 3). also, by having located the centre, you can now see what the radius is too, (just count horizontally or vertically from the centre till you hit the circumference) so radius is 4. The equation of a circle is r^2 = (x-{x coordinate of centre})^2 + (y - {y coordinate of centre})^2 note- r is radius. So you now want to substitute your radius and coordinates of the centre in, to find the circle-radius form
And as for the general form, you want to simplify the equation down and move everything (except the y) to the right hand side, in its simplest form
Ok thanks I'll try again and tag you if I need more help.. @FireKat97
no problem :)
figured it out thanks!

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