anonymous
  • anonymous
Hey guys. I need help on pre-cal. I don't really understand horizontal and vertical stretches besides the fact that "a stretch by a factor of c if c > 1" and "a shrink by a factor of c if c < 1" I will post the question below.
Mathematics
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anonymous
  • anonymous
Hey guys. I need help on pre-cal. I don't really understand horizontal and vertical stretches besides the fact that "a stretch by a factor of c if c > 1" and "a shrink by a factor of c if c < 1" I will post the question below.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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zepdrix
  • zepdrix
Whenever you `multiply y by something`, it corresponds to a `vertical stretch`. Whenever you `multiply x by something`, it corresponds to a `horizontal stretch`.
zepdrix
  • zepdrix
Think of f(x) as y.

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zepdrix
  • zepdrix
\[\large\rm \color{orangered}{y=\sqrt x}\]We achieve our new function multiplying both sides by 8,\[\large\rm 8\color{orangered}{y}=8\color{orangered}{\sqrt x}\] If f(x) = y Then g(x) = 8y This is a `vertical stretch` of f(x) by a factor of 8. We manipulated the y.
zepdrix
  • zepdrix
It might be confusing the way I said that you're `multiplying y by something`. But remember that this \(\large\rm \sqrt{x}\) is y. So when you multiply that by 8, you're multiplying y by 8, because that is y.
zepdrix
  • zepdrix
To make horizontal stretches, you multiply x by a value. Example:\[\large\rm f(x)=\sqrt{x}\qquad\to\qquad g(x)=\sqrt{4x}\]g(x) represents a `horizontal stretch` of f(x) by a factor of 4.
anonymous
  • anonymous
Thank you so much! No, I understood you completely it was much easier understanding your explanation than the textbook's. Thank you. :)
zepdrix
  • zepdrix
yay \c:/

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