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airyana1114
 one year ago
Can someone help me solve this equation? Step by Step.
airyana1114
 one year ago
Can someone help me solve this equation? Step by Step.

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1is it a hard equation ?

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x+6}4=x\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1oh no that can't be that hard

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me? I've never had this type of equation equaled to x and it sort of makes me nervous. Can you walk me through it? @misty1212

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yeah no problem first step is to get the radical by itself on one side of the equation by adding 4 to both sides, i.e. write \[\sqrt{x+6}=x+4\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1now you want to do it the math teacher way , or you want to think what the answer is , or both?

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure I understand what you're asking.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1we can find the answer in our head, but that is probably not what your math teacher wants you to do ,so lets go ahead and solve it the way they do in math class

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i can show you how to get the answer in your head second

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you want to get rid of the radical, so square both sides (carefully)

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0How would I square (x+4). Like this? x^2+8

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{x+6}=x+4\] square and get \[x+6=(x+4)^2\] or \[x+6=(x+4)(x+4)\] or \[x+6=x^2+8x+16\]

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0Where did the 8x come from?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1no dear that is not how you square \(x+4\) you have to write it as \[x(x+4)(x+4)=x^2+4x+4x+16=x^2+8x+16\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is that old "first outer inner last" stuff

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0Ohhhh, FOIL okay..that makes sense.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so now we have \[x+6=x^2+8x+16\] which is a quadratic equation we have to solve

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1set it equal to zero, get \[x^2+7x+10=0\] then factor

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2+7x+10=0\\ (x+2)(x+5)=0\] so \[x=2,x=5\] but we are not done yet

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you have to check the answer in the original equation not the quadratic equation if you do, you will see that \(x=2\) works but \(x=5\) does not

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0Making it an extraneous solution correct?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1right , which is a silly way of saying it is not a solution but no matter

airyana1114
 one year ago
Best ResponseYou've already chosen the best response.0:) thank you @misty1212

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\color\magenta\heartsuit\]
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