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anonymous
 one year ago
f(x)=(x^2)+1+(1/(x^4)), c=1; (a) find the slope of the line that is tangent to the graph of f(x) at the given point x=c; (b) write an equation of the tangent line to the graph of f(x) at the point (c,f(c))
anonymous
 one year ago
f(x)=(x^2)+1+(1/(x^4)), c=1; (a) find the slope of the line that is tangent to the graph of f(x) at the given point x=c; (b) write an equation of the tangent line to the graph of f(x) at the point (c,f(c))

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x)=x^2+1+\frac{1}{x^4}\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1do you know the derivative?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lol another county heard from you got \(f'(x)\) if not let me know

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get that the derivative is 2x(4/(x^5))

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok looks good plug in 1 what do you get?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok so \(m=2\) next i guess find \(f(1)\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1oh, the answer to question 1 was \(2\) now we can find the equation of the tangent line, once we have the point

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you construct the equation of the tangent line? I know in class we use yy1=m(xx1) and that m=f'(c) but what are y1 and x1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! duh! (c,f(c)). the question told me that. thanks!!
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