carolinar7
  • carolinar7
a ball is thrown straight upward with a speed of 20 m/s with what speed does the ball hit the ground?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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carolinar7
  • carolinar7
and i have another one the total time of all remains in the air is 14 seconds. a)with what speed was the ball thrown upwards b)what is the maximum height reached by the ball
carolinar7
  • carolinar7
I say 20m/s for the first one
carolinar7
  • carolinar7
|dw:1442888398239:dw|

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More answers

anonymous
  • anonymous
at highest point speed=0m/s v=u+gt 0=20-9.8 t t=20/9.8=2s approx time of flight=2*2=4s
anonymous
  • anonymous
yes you are correct.
carolinar7
  • carolinar7
what is the 0 in 0=20-9.8 t
anonymous
  • anonymous
speed at highest point.
carolinar7
  • carolinar7
what about the second question?
carolinar7
  • carolinar7
ok
anonymous
  • anonymous
forsecond take t=14/2=7 seconds and proceed as i have done.
carolinar7
  • carolinar7
idk
carolinar7
  • carolinar7
would the acceleration be + or-
carolinar7
  • carolinar7
+ right?
anonymous
  • anonymous
0=u-9.8*7 u=?
anonymous
  • anonymous
when going upward g is -ve,when going down g is +ve.
carolinar7
  • carolinar7
why are you using half the time why not the whole 14 seconds?
anonymous
  • anonymous
|dw:1442899612575:dw|
anonymous
  • anonymous
|dw:1442899702335:dw|
carolinar7
  • carolinar7
oh so would it be 69 m/s
carolinar7
  • carolinar7
for a)
carolinar7
  • carolinar7
oh and is it + or - accelaration?
anonymous
  • anonymous
69 m/s approx or68.6m/s
carolinar7
  • carolinar7
why is it - acceleration
carolinar7
  • carolinar7
if its going upwards
anonymous
  • anonymous
\[v^2-u^2=2as\]
anonymous
  • anonymous
because it is retardtion and speed is decreasing.
carolinar7
  • carolinar7
and for be is it 48x10 m
carolinar7
  • carolinar7
?
carolinar7
  • carolinar7
b) 48x10 m?
anonymous
  • anonymous
\[0^2-68.6^2=-2*9.8*h\] \[h=\frac{ 68.6*68.6 }{ 2*9.8 }=7*34.3=240.1m\]
carolinar7
  • carolinar7
a stone is dropped from 150 meters high .initial velocity is zero. a)with what speed does the stone strike the ground b)how long is the stone in the air c)sketch a position vs time graph for the stone
anonymous
  • anonymous
\[v^2-u^2=2gh\]
carolinar7
  • carolinar7
This is what I did \[\frac{ 69 m/s +0 m/s}{ 2 }(14 s) =Deltax\]
carolinar7
  • carolinar7
for the second question part b

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