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Pulsified333

  • one year ago

Assume that there are 13 board members: 8 females, and 5 males including Larry. There are 4 tasks to be assigned. Note that assigning the same people different tasks constitutes a different assignment. (1) Find the probability that both males and females are given a task. (2) Find the probability that Larry and at least one female are given tasks.

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  1. Pulsified333
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    what do you have so far?

  3. Pulsified333
    • one year ago
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    I have one of the answers right but I don't know which is right 1) 15360/17160 2) 864/17160

  4. jim_thompson5910
    • one year ago
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    let me think

  5. Pulsified333
    • one year ago
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    ok

  6. jim_thompson5910
    • one year ago
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    so it says that exactly one of your answers is correct?

  7. Pulsified333
    • one year ago
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    yeah I just don't know which

  8. jim_thompson5910
    • one year ago
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    hmm strange. I'm not getting either but I probably made a mistake somewhere. Let me double check

  9. Pulsified333
    • one year ago
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    I think the first one is right though

  10. jim_thompson5910
    • one year ago
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    this is what I keep getting m = male f = female problem (1) 3 m, 1 f = (5 npr 3)*(8 npr 1) = 480 2 m, 2 f = (5 npr 2)*(8 npr 2) = 1120 1 m, 3 f = (5 npr 1)*(8 npr 3) = 1680 total = 480+1120+1680 = 3280 # of outcomes = 13 npr 4 = 17160 probability = 3280/17160 Problem (2) Larry + 2 m + 1 f = (4)*(4 npr 2)*(8 npr 1) = 384 Larry + 1 m + 2 f = (4)*(4 npr 1)*(8 npr 2) = 896 Larry + 0 m + 3 f = (4)*(4 npr 0)*(8 npr 3) = 1344 total = 384+896+1344 = 2624 # of outcomes = 13 npr 4 = 17160 probability = 2624/17160

  11. Pulsified333
    • one year ago
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    For number 1 I got 17160-(1680+120)

  12. jim_thompson5910
    • one year ago
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    why did you compute it like that?

  13. Pulsified333
    • one year ago
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    https://answers.yahoo.com/question/index?qid=20110131185103AA6hK3T

  14. Pulsified333
    • one year ago
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    I followed this and I got that first answer but i don't understand how to do number 2

  15. Pulsified333
    • one year ago
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    I remember now it was the second one thats wrong

  16. jim_thompson5910
    • one year ago
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    ah I see now, that's a better way to do #1

  17. jim_thompson5910
    • one year ago
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    why not determine the number of ways to have Larry + 3 males then subtract that result from the total (17160) to figure out how many ways to have Larry + at least one female

  18. Pulsified333
    • one year ago
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    so how would you do that

  19. jim_thompson5910
    • one year ago
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    how many ways are there to assign tasks to Larry and 3 other males?

  20. Pulsified333
    • one year ago
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    40

  21. jim_thompson5910
    • one year ago
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    how did you get 40?

  22. Pulsified333
    • one year ago
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    well if larry has task A then that one thing. Then lets say he gets task B, that is different than task A

  23. Pulsified333
    • one year ago
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    so isnt there 4 different tasks that larry could be assigned

  24. jim_thompson5910
    • one year ago
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    so he has 4 choices, yes

  25. Pulsified333
    • one year ago
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    C(5,3)*4

  26. jim_thompson5910
    • one year ago
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    5-1 = 4 males left 4-1 = 3 slots left Compute P(4,3)

  27. Pulsified333
    • one year ago
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    oh

  28. Pulsified333
    • one year ago
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    24?

  29. jim_thompson5910
    • one year ago
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    then you multiply that by 4 4*P(4,3) = 4*24 = 96

  30. jim_thompson5910
    • one year ago
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    there are 96 ways to pick Larry + 3 other males

  31. Pulsified333
    • one year ago
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    okay so 17160-96?

  32. jim_thompson5910
    • one year ago
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    hmm now that I think about it, that computes the number of ways to pick everything the opposite of "Larry + 3 other males" so larry is left out. Let me rethink

  33. jim_thompson5910
    • one year ago
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    did you see how I did problem 2 above? I'm guessing that answer didn't work?

  34. Pulsified333
    • one year ago
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    I didn't try it yet

  35. Pulsified333
    • one year ago
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    but yes I saw how you did it

  36. jim_thompson5910
    • one year ago
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    give it a try. It's probably wrong but I initially thought it was the correct way to do it

  37. Pulsified333
    • one year ago
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    well i only have 4 attempts left so

  38. Pulsified333
    • one year ago
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    look at how this person did number two for a similar but not the same problem http://www.jiskha.com/display.cgi?id=1236051521

  39. Pulsified333
    • one year ago
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    @satellite73

  40. Pulsified333
    • one year ago
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    I have no clue how to find the second answer

  41. Pulsified333
    • one year ago
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    @dan815

  42. Pulsified333
    • one year ago
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    @jim_thompson5910 i have no clue how to find the second answer

  43. jim_thompson5910
    • one year ago
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    same here. I'm still trying to decipher what that other poster wrote

  44. jim_thompson5910
    • one year ago
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    there are (13 npr 4) - (12 npr 4) = 5,280 ways to have 4 people chosen where Larry is one of the 4 people

  45. jim_thompson5910
    • one year ago
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    as for the other piece, hmm, I'm thinking there are (12 npr 3) - (4 npr 3) = 1,296 ways to pick at least one female

  46. jim_thompson5910
    • one year ago
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    so maybe we multiply the results to get 5,280*1,296 = 6,842,880 that result seems way too big though

  47. Pulsified333
    • one year ago
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    it is because its bigger than the total number of ways

  48. jim_thompson5910
    • one year ago
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    good point

  49. Pulsified333
    • one year ago
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    I found it :D 216/715

  50. jim_thompson5910
    • one year ago
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    I'm curious as to how you got that

  51. Pulsified333
    • one year ago
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    My friend helped me with that so he's gonna explain it to me tomorrow thank you for trying though

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