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x1= 200/ tan 17°44' = ..
x2 = 200/ tan 48°13' = ...
The distance it traveled:
x₁ - x₂ = ...

|dw:1442888207816:dw|
You want to find x

|dw:1442888438629:dw| Start by finding theta and using theta find y

how would i find theta?

would it be 90 - 48°13'

im so lost

B = theta + 48°13'

Yup theta is correct
sorry I marked beta wrong its |dw:1442888983577:dw|

so, now that you have theta, and you're already given one side, you can find y using trig

how? like which theorem?

sin

y/200

jk

tan, y/200

yup thats right

so y = ?

it is y=0.36397023

jk tan(1/200)y)

umm actually by using tan, we get;
tanø = y/200
so y = 200.tanø

do you see why?

ohh ok
yes

yup, and you know what theta is, you had it right before, so sub theta in, to find y.

y = 200.tan(90 - 48°13')

yes thats correct! now, we can apply the same techniques, to find z, tell me what you get for z

do i use B

yup, use beta

B = theta + 48°13'

B = (90 - 48°13')+ 48°13'

hang on, use this diagram|dw:1442890296933:dw|

|dw:1442890336639:dw|

hopefully thats clearer

so can you see how you would resolve for beta?

not really ;(

like what formula should i use

beta = 90 - 48°13'

beta = 90 - 17 degrees 44 minutes

do you see why?

My diagrams are really bad hahah sorry about that

sorry i took so long to respond!

tan(z/200) = beta
= tan(z/200)= 90- 17 degrees 44 minutes

y=449.20