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anonymous
 one year ago
A sequence {an} is defined recursively, with a1 = 1, and, for n > 1, an = an1 + (1)n. Find the first five terms of the sequence.
A)
1, 0, 1, 2, 3
B)
1, 2, 3, 4, 5
C)
1, 0, 1, 0, 1
D)
1, 1, 1, 1, 1
anonymous
 one year ago
A sequence {an} is defined recursively, with a1 = 1, and, for n > 1, an = an1 + (1)n. Find the first five terms of the sequence. A) 1, 0, 1, 2, 3 B) 1, 2, 3, 4, 5 C) 1, 0, 1, 0, 1 D) 1, 1, 1, 1, 1

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johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1\(\large a_1 = 1\) and for \(\large n>1\) \(\large a_n = a_{n1} + (1)^n\) Like that?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1I'm just seeing if I wrote it correctly as you have on your paper?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Okay So we know the first term is 1...we are given that...so \(\large a_1 = 1\) Now for \(\large a_2\) since we are now > 1 ...we use that equation \[\large a_n = a_{n1} + 1^n\] So for n= 2 *the second term \[\large a_2 = a_{21} + 1^2\] \[\large a_2 = a_1 + 1^2\] We know \(\large a_1\) = 1 so we can replace that \[\large a_2 = 1 + 1^2\] What is 1^2? 1 * 1 = 1 right? so \[\large a_2 = 1 + 1 = ?\]
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