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anonymous

  • one year ago

(2x − 3)^3 Perform operations and simplify

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  1. Nnesha
    • one year ago
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    are you working on binomial theorem ?

  2. Nnesha
    • one year ago
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    binomial theorem for (x-y)^3\[\huge\rm (x-y)^3 = x^3-3x^2y+3xy^2-y^3\]

  3. anonymous
    • one year ago
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    can you tell me the answer please i've already tried the question and got the worng ansewr @Nnesha

  4. Nnesha
    • one year ago
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    alright then show ur work plz so i can find out the mistakes so we don;t have to restart it again

  5. anonymous
    • one year ago
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    i don'thave me work with me...it's an online assignment...

  6. Nnesha
    • one year ago
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    no i mean how did you get the wrong answer ? i just want to know where u did a mistake

  7. anonymous
    • one year ago
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    I don't know where i made a mistake...

  8. Nnesha
    • one year ago
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    \[\huge\rm (x-y)^3 = x^3-3x^2y+3xy^2-y^3\]use this equation cube of first term `-` 3 times (square of first term times 2nd term) + 3 times first term times square of 2nd term - cube of 2nd term

  9. Nnesha
    • one year ago
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    ye ik so that's why i'm saying post your work here maybe i will be able to find the mistake :=)

  10. anonymous
    • one year ago
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    I'm not goingto type all my work out right now

  11. Nnesha
    • one year ago
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    ok.as you wish .

  12. Nnesha
    • one year ago
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    i asked a question would you like to answer that or no sir ????

  13. anonymous
    • one year ago
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    First off...I'm not a sir...Secondly it's not a quiz or anything, i got the answer wrong multiple times and would just like to know the answer...

  14. Nnesha
    • one year ago
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    alright sorry about that mam i can't give you the answer you got the answer wrong it's okay i'm saying it would be great to just look over ur work and find the mistake instead wasting time doing it again.

  15. Nnesha
    • one year ago
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    by just looking at the answer how would you find the mistake ?

  16. Nnesha
    • one year ago
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    anyways i'll do the first term (x-y)^3\[\huge\rm (x-y)^3 =\color{ReD}{ x^3}-\color{blue}{3x^2y}+3xy^2-y^3\] in your question 2x is the first term \[\huge\rm (2x-y)^3= \color{Red}{(2x)^3 - \color{blue}{3(2x)^2(-y)}}\]

  17. anonymous
    • one year ago
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    I've done it with multiple problems...if i know the answer i can get the work easier

  18. Nnesha
    • one year ago
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    better use calculator then. sorry

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