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anonymous

  • one year ago

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers. Note:only show the problem and the way you work it out.

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  1. anonymous
    • one year ago
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    we need a variable for the first number you pick

  2. anonymous
    • one year ago
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    ok

  3. anonymous
    • one year ago
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    what do you pick?

  4. anonymous
    • one year ago
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    x

  5. anonymous
    • one year ago
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    lol no imagination, i would have picked \(\spadesuit\) but \(x\) will do

  6. anonymous
    • one year ago
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    if the first number is \(x\) and the second number is three times that, how you would write three times \(x\)?

  7. anonymous
    • one year ago
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    i am doing this on a website called mineracademy. owschool.com and it wont let me use that type of stuff only regular keyboard stuff so....yea

  8. anonymous
    • one year ago
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    how would you write three times x?

  9. anonymous
    • one year ago
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    3*x

  10. anonymous
    • one year ago
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    ok

  11. anonymous
    • one year ago
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    then how would you write (this is the only hard part) ten less that two times x ?

  12. anonymous
    • one year ago
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    10-(2*x)

  13. anonymous
    • one year ago
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    yeah i thought this was the hard part, so lets go slow

  14. anonymous
    • one year ago
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    if x was 40 then ten less than two times x would be ten less than 80 i.e 70

  15. anonymous
    • one year ago
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    first multiply by 2, THEN subtract 10

  16. anonymous
    • one year ago
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    dude i am in 9th grade that part wasn't so hard my top classes are economics and english in 8th grade in reading on my Iowa test i got the adverage of a 12th grader.

  17. anonymous
    • one year ago
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    economics i never even heard of in 9th grade in any case "ten less than two times x" would translate as \[2x-10\]

  18. anonymous
    • one year ago
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    now add them up and set the result equal to \(92\) i.e solve \[x+3x+2x-10=92\]

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