anonymous
  • anonymous
The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers. Note:only show the problem and the way you work it out.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
we need a variable for the first number you pick
anonymous
  • anonymous
ok
anonymous
  • anonymous
what do you pick?

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More answers

anonymous
  • anonymous
x
anonymous
  • anonymous
lol no imagination, i would have picked \(\spadesuit\) but \(x\) will do
anonymous
  • anonymous
if the first number is \(x\) and the second number is three times that, how you would write three times \(x\)?
anonymous
  • anonymous
i am doing this on a website called mineracademy. owschool.com and it wont let me use that type of stuff only regular keyboard stuff so....yea
anonymous
  • anonymous
how would you write three times x?
anonymous
  • anonymous
3*x
anonymous
  • anonymous
ok
anonymous
  • anonymous
then how would you write (this is the only hard part) ten less that two times x ?
anonymous
  • anonymous
10-(2*x)
anonymous
  • anonymous
yeah i thought this was the hard part, so lets go slow
anonymous
  • anonymous
if x was 40 then ten less than two times x would be ten less than 80 i.e 70
anonymous
  • anonymous
first multiply by 2, THEN subtract 10
anonymous
  • anonymous
dude i am in 9th grade that part wasn't so hard my top classes are economics and english in 8th grade in reading on my Iowa test i got the adverage of a 12th grader.
anonymous
  • anonymous
economics i never even heard of in 9th grade in any case "ten less than two times x" would translate as \[2x-10\]
anonymous
  • anonymous
now add them up and set the result equal to \(92\) i.e solve \[x+3x+2x-10=92\]

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