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- anonymous

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers.
Note:only show the problem and the way you work it out.

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- anonymous

- chestercat

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- anonymous

we need a variable for the first number
you pick

- anonymous

ok

- anonymous

what do you pick?

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- anonymous

x

- anonymous

lol no imagination, i would have picked \(\spadesuit\) but \(x\) will do

- anonymous

if the first number is \(x\) and the second number is three times that, how you would write three times \(x\)?

- anonymous

i am doing this on a website called mineracademy. owschool.com and it wont let me use that type of stuff only regular keyboard stuff so....yea

- anonymous

how would you write three times x?

- anonymous

3*x

- anonymous

ok

- anonymous

then how would you write (this is the only hard part) ten less that two times x ?

- anonymous

10-(2*x)

- anonymous

yeah i thought this was the hard part, so lets go slow

- anonymous

if x was 40 then ten less than two times x would be ten less than 80 i.e 70

- anonymous

first multiply by 2, THEN subtract 10

- anonymous

dude i am in 9th grade that part wasn't so hard my top classes are economics and english in 8th grade in reading on my Iowa test i got the adverage of a 12th grader.

- anonymous

economics i never even heard of in 9th grade
in any case "ten less than two times x" would translate as
\[2x-10\]

- anonymous

now add them up and set the result equal to \(92\) i.e solve \[x+3x+2x-10=92\]

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