anonymous
  • anonymous
Find the difference and simplify: 2/(x^2+3x) - 3/(x^2-9)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
\[\huge\rm \frac{ 2 }{ x^2+3x }-\frac{ 3 }{ x^2-9 }\] factor the denominator
anonymous
  • anonymous
X(x+3)(x-3) ??
Nnesha
  • Nnesha
for x^2-9 apply the difference of squares \[\huge\rm a^2-b^2=(a+b)(a-b)\] do you mean x(x+3)(x-3) is a common denominator ?

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More answers

anonymous
  • anonymous
Yes
Luigi0210
  • Luigi0210
I think he went straight to the common denominator (:
Nnesha
  • Nnesha
true >.<
anonymous
  • anonymous
Would the answer be -1/ x(x+3)(x-3) ??
Nnesha
  • Nnesha
alright then when we find common denominator we should multiply the numerator of 1st fraction with the denominator of the 2nd fraction and multiply the numerator of 2nd fraction with the denominator of first fraction (just like cross multiplication ) here is an example |dw:1442889917081:dw|
Nnesha
  • Nnesha
hmm no how did you get that ?
Nnesha
  • Nnesha
show ur work plz so i can find ot the mistakes :=)
anonymous
  • anonymous
I just subtracted 2-3 and got -1 and used the common denominator. I actually dont know what im doing but im trying
Mertsj
  • Mertsj
\[\frac{2}{x(x+3)}\times\frac{x-3}{x-3}-\frac{3}{(x-3)(x+3)}\times\frac{x}{x}\]
Nnesha
  • Nnesha
hm no you can't do that
anonymous
  • anonymous
Explain please?
Nnesha
  • Nnesha
just like i said multiply the numerator of first fraction with the `denominator ` of 2nd fraction so \[\huge\rm \frac{ 2 }{ x(x+3) } -\frac{ 3 }{ (x+3)(x-3) }\] x(x+3)(x-3) is a common denominator so multiply first fraction with x-3 and 2nd fraction with x
anonymous
  • anonymous
Would the numerator be x+6??
Nnesha
  • Nnesha
\[\huge\rm \frac{ 2(x-3)-3(x) }{ x (x+3)(x-3)}\] distribute the parentheses by 2 and then combine like terms
Nnesha
  • Nnesha
2(x-3) = ?
anonymous
  • anonymous
2x-6
Nnesha
  • Nnesha
yes right so \[\huge\rm \frac{\color{Red}{ 2x-6-3x} }{ x (x+3)(x-3)}\] now combine like terms
anonymous
  • anonymous
Would it he -x-6 / x(x+3)(x-3) ?!?!
Nnesha
  • Nnesha
yes right "=)
anonymous
  • anonymous
Omg thank you so much!
Nnesha
  • Nnesha
np :=)

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