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anonymous

  • one year ago

Find the difference and simplify: 2/(x^2+3x) - 3/(x^2-9)

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  1. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 2 }{ x^2+3x }-\frac{ 3 }{ x^2-9 }\] factor the denominator

  2. anonymous
    • one year ago
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    X(x+3)(x-3) ??

  3. Nnesha
    • one year ago
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    for x^2-9 apply the difference of squares \[\huge\rm a^2-b^2=(a+b)(a-b)\] do you mean x(x+3)(x-3) is a common denominator ?

  4. anonymous
    • one year ago
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    Yes

  5. Luigi0210
    • one year ago
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    I think he went straight to the common denominator (:

  6. Nnesha
    • one year ago
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    true >.<

  7. anonymous
    • one year ago
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    Would the answer be -1/ x(x+3)(x-3) ??

  8. Nnesha
    • one year ago
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    alright then when we find common denominator we should multiply the numerator of 1st fraction with the denominator of the 2nd fraction and multiply the numerator of 2nd fraction with the denominator of first fraction (just like cross multiplication ) here is an example |dw:1442889917081:dw|

  9. Nnesha
    • one year ago
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    hmm no how did you get that ?

  10. Nnesha
    • one year ago
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    show ur work plz so i can find ot the mistakes :=)

  11. anonymous
    • one year ago
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    I just subtracted 2-3 and got -1 and used the common denominator. I actually dont know what im doing but im trying

  12. Mertsj
    • one year ago
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    \[\frac{2}{x(x+3)}\times\frac{x-3}{x-3}-\frac{3}{(x-3)(x+3)}\times\frac{x}{x}\]

  13. Nnesha
    • one year ago
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    hm no you can't do that

  14. anonymous
    • one year ago
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    Explain please?

  15. Nnesha
    • one year ago
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    just like i said multiply the numerator of first fraction with the `denominator ` of 2nd fraction so \[\huge\rm \frac{ 2 }{ x(x+3) } -\frac{ 3 }{ (x+3)(x-3) }\] x(x+3)(x-3) is a common denominator so multiply first fraction with x-3 and 2nd fraction with x

  16. anonymous
    • one year ago
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    Would the numerator be x+6??

  17. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 2(x-3)-3(x) }{ x (x+3)(x-3)}\] distribute the parentheses by 2 and then combine like terms

  18. Nnesha
    • one year ago
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    2(x-3) = ?

  19. anonymous
    • one year ago
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    2x-6

  20. Nnesha
    • one year ago
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    yes right so \[\huge\rm \frac{\color{Red}{ 2x-6-3x} }{ x (x+3)(x-3)}\] now combine like terms

  21. anonymous
    • one year ago
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    Would it he -x-6 / x(x+3)(x-3) ?!?!

  22. Nnesha
    • one year ago
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    yes right "=)

  23. anonymous
    • one year ago
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    Omg thank you so much!

  24. Nnesha
    • one year ago
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    np :=)

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