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anonymous
 one year ago
Find the difference and simplify:
2/(x^2+3x)  3/(x^29)
anonymous
 one year ago
Find the difference and simplify: 2/(x^2+3x)  3/(x^29)

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \frac{ 2 }{ x^2+3x }\frac{ 3 }{ x^29 }\] factor the denominator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1for x^29 apply the difference of squares \[\huge\rm a^2b^2=(a+b)(ab)\] do you mean x(x+3)(x3) is a common denominator ?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0I think he went straight to the common denominator (:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would the answer be 1/ x(x+3)(x3) ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright then when we find common denominator we should multiply the numerator of 1st fraction with the denominator of the 2nd fraction and multiply the numerator of 2nd fraction with the denominator of first fraction (just like cross multiplication ) here is an example dw:1442889917081:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hmm no how did you get that ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1show ur work plz so i can find ot the mistakes :=)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just subtracted 23 and got 1 and used the common denominator. I actually dont know what im doing but im trying

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{2}{x(x+3)}\times\frac{x3}{x3}\frac{3}{(x3)(x+3)}\times\frac{x}{x}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hm no you can't do that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1just like i said multiply the numerator of first fraction with the `denominator ` of 2nd fraction so \[\huge\rm \frac{ 2 }{ x(x+3) } \frac{ 3 }{ (x+3)(x3) }\] x(x+3)(x3) is a common denominator so multiply first fraction with x3 and 2nd fraction with x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would the numerator be x+6??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \frac{ 2(x3)3(x) }{ x (x+3)(x3)}\] distribute the parentheses by 2 and then combine like terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right so \[\huge\rm \frac{\color{Red}{ 2x63x} }{ x (x+3)(x3)}\] now combine like terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would it he x6 / x(x+3)(x3) ?!?!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Omg thank you so much!
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