Pulsified333
  • Pulsified333
involving sets E and F. Suppose for this problem that Pr[E]=1/2, Pr[F]=5/16, and Pr[E∩F′]=1/4. (1) What is Pr[E|F]? (2) What is Pr[F|E]?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
misty1212
  • misty1212
must be some typo here does it really say \[P(E)=12\]??
Pulsified333
  • Pulsified333
sorry i forgot to fix the fractions
misty1212
  • misty1212
or is that maybe \[P(E)=\frac{1}{2}\]?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Pulsified333
  • Pulsified333
its 1/2
misty1212
  • misty1212
how about the rest?
misty1212
  • misty1212
oh nvm i see they are fixed
Pulsified333
  • Pulsified333
:)
misty1212
  • misty1212
in any case \[P(A|B)=\frac{P(A\cap B)}{P(B)}\]
misty1212
  • misty1212
so \[P(E|F)=\frac{P(E\cap F)}{P(F)}\] how have those numbers
misty1212
  • misty1212
l meant "you" have those numbers
Pulsified333
  • Pulsified333
we don't have P(E∩F)
misty1212
  • misty1212
looks like you wrote it was \(\frac{1}{4}\)
Pulsified333
  • Pulsified333
that is Pr[E∩F′]=1/4.
Pulsified333
  • Pulsified333
not the same thing as P(E∩F)
misty1212
  • misty1212
|dw:1442890782534:dw|
misty1212
  • misty1212
you can find \[P(E\cap F)\] by subtracting \[P(E\cap F')\] from \(P(E)\)
Pulsified333
  • Pulsified333
really?
misty1212
  • misty1212
can you see it in the picture?
Pulsified333
  • Pulsified333
so you are saying its 1/4
misty1212
  • misty1212
|dw:1442891040553:dw||dw:1442891076272:dw|
Pulsified333
  • Pulsified333
so its (1/4)/(5/16)
misty1212
  • misty1212
yeah in your case it is \(\frac{1}{4}\)
misty1212
  • misty1212
and yes, your answer is right (after you do the math)
Pulsified333
  • Pulsified333
so its 4/5
misty1212
  • misty1212
yes
Pulsified333
  • Pulsified333
and then #2 is 1/2
misty1212
  • misty1212
yes
Pulsified333
  • Pulsified333
thank you :D can you help me on another one?

Looking for something else?

Not the answer you are looking for? Search for more explanations.