anonymous
  • anonymous
Find the quotient and simplify: X+3/ x^2 ÷ (x^2-9)/ 4x^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jackthegreatest
  • jackthegreatest
hi ashley i can help
anonymous
  • anonymous
Hey! Thank you!
jackthegreatest
  • jackthegreatest
so right now, do u have any idea wat ur first step should be?

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anonymous
  • anonymous
Im really not sure
jackthegreatest
  • jackthegreatest
k
jackthegreatest
  • jackthegreatest
well first of all, u dont want a fraction divided by a fraction
anonymous
  • anonymous
Alright
jackthegreatest
  • jackthegreatest
so u could get rid of the second fraction by flipping the top with the bottom
anonymous
  • anonymous
Will the denominator be x-3 ?
jackthegreatest
  • jackthegreatest
\[\frac{ x+3 }{ x^{2} } \times \frac{ x^{2} - 9 }{ 4x^{2} }\]
jackthegreatest
  • jackthegreatest
do u know how to cross multiply?
anonymous
  • anonymous
Yes
jackthegreatest
  • jackthegreatest
actually after thinking about it, u dont need to cross multiply, just multiply the top with the top and the bottom with the bottom
anonymous
  • anonymous
Im not sure im following
jackthegreatest
  • jackthegreatest
Hold on a sec
jackthegreatest
  • jackthegreatest
I'm gonna post a pic of my steps
anonymous
  • anonymous
Okayy
anonymous
  • anonymous
What would the denominator be?
jackthegreatest
  • jackthegreatest
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jackthegreatest
  • jackthegreatest
there finally i got it by using mail from my phone to computer
anonymous
  • anonymous
I understand thay now that you for helping me !!
jackthegreatest
  • jackthegreatest
welcome!
anonymous
  • anonymous
Okay i have another problem. X/2 ÷ 5y/2 would the answer be x/5y ??
anonymous
  • anonymous
@jackthegreatest
jackthegreatest
  • jackthegreatest
yep!! congrats! u got it right!
anonymous
  • anonymous
Yay thank you!
jackthegreatest
  • jackthegreatest
if any more questions come up just post up a new questions, that way more people could help u as well : )
jackthegreatest
  • jackthegreatest
and just tag me and i shall be summoned... lol
anonymous
  • anonymous
Lol okay thank you again

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