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anonymous

  • one year ago

Find the quotient and simplify: X+3/ x^2 ÷ (x^2-9)/ 4x^2

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  1. jackthegreatest
    • one year ago
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    hi ashley i can help

  2. anonymous
    • one year ago
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    Hey! Thank you!

  3. jackthegreatest
    • one year ago
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    so right now, do u have any idea wat ur first step should be?

  4. anonymous
    • one year ago
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    Im really not sure

  5. jackthegreatest
    • one year ago
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    k

  6. jackthegreatest
    • one year ago
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    well first of all, u dont want a fraction divided by a fraction

  7. anonymous
    • one year ago
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    Alright

  8. jackthegreatest
    • one year ago
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    so u could get rid of the second fraction by flipping the top with the bottom

  9. anonymous
    • one year ago
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    Will the denominator be x-3 ?

  10. jackthegreatest
    • one year ago
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    \[\frac{ x+3 }{ x^{2} } \times \frac{ x^{2} - 9 }{ 4x^{2} }\]

  11. jackthegreatest
    • one year ago
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    do u know how to cross multiply?

  12. anonymous
    • one year ago
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    Yes

  13. jackthegreatest
    • one year ago
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    actually after thinking about it, u dont need to cross multiply, just multiply the top with the top and the bottom with the bottom

  14. anonymous
    • one year ago
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    Im not sure im following

  15. jackthegreatest
    • one year ago
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    Hold on a sec

  16. jackthegreatest
    • one year ago
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    I'm gonna post a pic of my steps

  17. anonymous
    • one year ago
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    Okayy

  18. anonymous
    • one year ago
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    What would the denominator be?

  19. jackthegreatest
    • one year ago
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  20. jackthegreatest
    • one year ago
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    there finally i got it by using mail from my phone to computer

  21. anonymous
    • one year ago
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    I understand thay now that you for helping me !!

  22. jackthegreatest
    • one year ago
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    welcome!

  23. anonymous
    • one year ago
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    Okay i have another problem. X/2 ÷ 5y/2 would the answer be x/5y ??

  24. anonymous
    • one year ago
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    @jackthegreatest

  25. jackthegreatest
    • one year ago
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    yep!! congrats! u got it right!

  26. anonymous
    • one year ago
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    Yay thank you!

  27. jackthegreatest
    • one year ago
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    if any more questions come up just post up a new questions, that way more people could help u as well : )

  28. jackthegreatest
    • one year ago
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    and just tag me and i shall be summoned... lol

  29. anonymous
    • one year ago
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    Lol okay thank you again

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