KJ4UTS
  • KJ4UTS
For each of the following tables of data, determine whether the data is linear, quadratic or neither. Please explain. Thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
KJ4UTS
  • KJ4UTS
KJ4UTS
  • KJ4UTS
2.1204-1.5203 = 0.6001 2.9574-2.1204 = 0.837 4.1248-2.9574 = 1.1674 5.7531-4.1248 = 1.6283
KJ4UTS
  • KJ4UTS

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

KJ4UTS
  • KJ4UTS
4.454-2.342 = 2.112 6.566-4.454 = 2.112 8.678-6.566 = 2.112 10.790-8.678 = 2.112
KJ4UTS
  • KJ4UTS
KJ4UTS
  • KJ4UTS
3.128-1.232 = 1.896 5.888-3.128 = 2.76 9.512-5.888 = 3.624 14.0-9.512 = 4.488
KJ4UTS
  • KJ4UTS
How do I know if its linear, quadratic or neither, I think I did the work right?
KJ4UTS
  • KJ4UTS
I think the second one is linear?
FireKat97
  • FireKat97
I was thinking along the same lines as you... tbh Im not too sure about this one either :/
KJ4UTS
  • KJ4UTS
I think I got it the second one is linear because the y differences equal and the third one is quadratic because the 2nd differences equal. I have not checked the first one yet.
KJ4UTS
  • KJ4UTS
The first one looks like neither linear nor quadratic.
anonymous
  • anonymous
Linear is when the difference between the points are all the same. Quadratic is when the difference between the points are increasing or deceasing each time. Neither is when it increases slower or decreases slower each time.
anonymous
  • anonymous
For me number one is quadratic.
anonymous
  • anonymous
Quadratic equation consist of parabola |dw:1442894201527:dw| The slopes increase in a parabola.
anonymous
  • anonymous
Just like the slopes of number one.
anonymous
  • anonymous
Linear is y=mx+b Let m be 5 and b be 2 (0,2) (1,7) (2,12) The difference is 5 for each one.
anonymous
  • anonymous
Nice job attempting it though.
KJ4UTS
  • KJ4UTS
Thank you! I turned in the assignment and going from top to bottom: 1. Neither 2. Linear 3. Quadratic
anonymous
  • anonymous
Does it have to be one of each?
KJ4UTS
  • KJ4UTS
For number 1 if you subtract the seconds you get different results: 2.1204-1.5203 = 0.6001 2.9574-2.1204 = 0.837 4.1248-2.9574 = 1.1674 5.7531-4.1248 = 1.6283 0.837-0.6001= 0.2369 1.1674-0.837=0.3304 1.16283-1.1674=0.4609 All different means its neither. For number 2 all the y's are the same: 4.454-2.342 = 2.112 6.566-4.454 = 2.112 8.678-6.566 = 2.112 10.790-8.678 = 2.112 Making it linear. For number 3 if you subtract the 2nds you get 18.4 for all of them: 3.128-1.232 = 1.896 5.888-3.128 = 2.76 9.512-5.888 = 3.624 14.0-9.512 = 4.488 4.488-3.624 = 18.4 3.624-2.76 = 18.4 2.76-1.896 = 18.4 2nds all the same mean its quadratic.
anonymous
  • anonymous
4.488-3.624 = 18.4 3.624-2.76 = 18.4 2.76-1.896 = 18.4 Its 0.864
anonymous
  • anonymous
Yes you are correct. Sorry for mentioning the wrong one on number one.
anonymous
  • anonymous
I didnt calculate the change of slope because I didnt have a calculator with me. 1. somewhat looks quadratic without a calculator lol.
KJ4UTS
  • KJ4UTS
No problem thanks for your time and help. Thank you for catching me on that mistake, the answer was 18.4 was for a question and I got mixed up on all the work I did on paper: Consider the quadratic function f(x)=2.3x^2+5.2x-6.7 with the input values x = 2, 4, 6, 8 and 10 and I had to determine the constant value of the second differences and it was 18.4
KJ4UTS
  • KJ4UTS
I am just a little tired I guess lol, have a great night :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.