A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Need help getting started on this question. Thanks

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The steel ingot shown in Fig. 2 has a mass of 1800 kg. It travels along the conveyor at a speed v = 0.5 m/s when it collides with the nested spring assembly. Determine the maximum deflections in each spring needed to stop the motion of the ingot, if kA = 5 kN/m and kB = 3 kN/m.

    1 Attachment
  2. Koikkara
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm not sure how to solve it, but \(answer\) comes approx = to \(11.1~kN/m\)

  3. Koikkara
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The way i found is .... The kinetic energy of the ingot is \(K.E. = 1/2 m*v^2\) = \(1/2* 1800 * 0.5^2\) = 225 J For the ingot to stop, the springs must decrease the kinetic energy until it is zero, this energy is stored as potential energy in the spring. therefore \(P.E. = K.E. =225 J \) Now to find, Potential energy stored in the springs: \(P.E. = 1/2( k1* x1^2 + k2*x2^2) \) And when the ingot is 0.3m from the wall, the compression of 2 springs : \(x1 = 0.5 - 0.3 = 0.2 m \) \(x2 = 0.45 - 0.3 = 0.15 m\), where spring 1 in the outer spring \(Substituting\), values and the spring constant for the outer spring: \(P.E. = 225 = 1/2( 5000* 0.2^2 + k2*0.15^2) \) \(= 225 = 1/2( 200 + k2*0.0225) \) rRearranging in terms of k2, \(k2 = (2*225 - 200)/0.0225 \) \(= 11.1 kN/m \) @ohernand

  4. mathmate
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I am not sure if you are solving the same problem as in the figure. In your question, ka and kb are given, and there is a 5 cm distance between the beginning of the two spring. We're expected to find the \(distance\) when the block stops. Your solution calculates k2, which seems to be a different problem with given displacements. So please clarify.

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.