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anonymous
 one year ago
Could use some help getting started with this question. Thanks
anonymous
 one year ago
Could use some help getting started with this question. Thanks

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The steel ingot shown in Fig. 2 has a mass of 1800 kg. It travels along the conveyor at a speed v = 0.5 m/s when it collides with the nested spring assembly. Determine the maximum deflections in each spring needed to stop the motion of the ingot, if kA = 5 kN/m and kB = 3 kN/m.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0when it stops, the KE of the ingot will temporarily be stored as PE in the springs, and generally speaking we can say \(PE = \frac{1}{2}kx^2\) here you will have different extensions (NB read: compressions) as the springs are staggered [we assume that the first spring will not stop the ingot in 0.1m but you can check that first if you like thus we combine energy in the springs for a general extension x as \(PE = \frac{1}{2} \left[ k_a x^2 + k_b (x0.1)^2\right]\) hopefully \(x \lt 0.5\) or something is broken....
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