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anonymous
 one year ago
Not sure where to start for number 4 and 5. I think I got the first part of 4 right but unsure!! Any help is greatly appreciated!!!
anonymous
 one year ago
Not sure where to start for number 4 and 5. I think I got the first part of 4 right but unsure!! Any help is greatly appreciated!!!

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05. A 39,250 N force is applied to a 7200kg car initially at rest . what is the acceleration rate? How fast will the car be moving after 3,8 seconds? Sorry if you couldn't see the picture.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1use newton's second law \(F=ma\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.039,250 =7200 *a 39,250/7200 =a=5.5 m/s

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1careful about the units a=5.5 m/s^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. How do I calculate how fast it's going to be after 3.8 seconds. Do I use v=10 * t but that has something to od with free fall? So, no?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1so the car is being accelerated for 3.8 seconds

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(a = 5.5\) \(t=3.8\) initial velocity, \(u=0\) final velocity, \(v=?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05.58 * 3.8 =20.9 m/s

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1right, but it seems you have a rounding error.. maybe just enter below into the calculator : 39250/7200*3.8 = 20.7 m/s

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok . I think I understand. Thank you so much!!!!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1as you can see, "change in speed" requires acceleration no acceleration means no "change in speed"
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