A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Not sure where to start for number 4 and 5. I think I got the first part of 4 right but unsure!! Any help is greatly appreciated!!!

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    5. A 39,250 N force is applied to a 7200kg car initially at rest . what is the acceleration rate? How fast will the car be moving after 3,8 seconds? Sorry if you couldn't see the picture.

  2. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    use newton's second law \(F=ma\)

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    39,250 =7200 *a 39,250/7200 =a=5.5 m/s

  4. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    careful about the units a=5.5 m/s^2

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok. How do I calculate how fast it's going to be after 3.8 seconds. Do I use v=10 * t but that has something to od with free fall? So, no?

  6. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so the car is being accelerated for 3.8 seconds

  7. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(a = 5.5\) \(t=3.8\) initial velocity, \(u=0\) final velocity, \(v=?\)

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    5.58 * 3.8 =20.9 m/s

  9. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    right, but it seems you have a rounding error.. maybe just enter below into the calculator : 39250/7200*3.8 = 20.7 m/s

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok . I think I understand. Thank you so much!!!!

  11. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yw!

  12. ganeshie8
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    as you can see, "change in speed" requires acceleration no acceleration means no "change in speed"

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.