Systems of Equations, please help =) Solve without matrix 5x-y+z=4; x+2y-2=5; 2x+3y-3=5 I have the answer, but have tried multiple times and cannot get to it.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Systems of Equations, please help =) Solve without matrix 5x-y+z=4; x+2y-2=5; 2x+3y-3=5 I have the answer, but have tried multiple times and cannot get to it.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

WAIT that's the wrong equation!! It's 5x-y+Z=4, x+2y-Z=5, 2x+3y+3Z=5
so which letter do you want to eliminate... y or z..?
Whichever is easier.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

ok... so we'll eliminate z you'll end up with 2 equations in 2 unknowns so add equations 1 and 2 5x -y + z = 4 x + 2y - z = 5 -------------- 6x + y = 9 equation 4 now multiply equation 2 by 3 and add equation 3 3x + 6y -3z = 15 2x + 3y + 3z = 5 ----------------- 5x + 9y = 20 equation 5 easiest thing to do now is to multiply equation 4 by 9 and subtract equation 5 which will eliminate y 54x + 9y = 81 - 5x - 9y = -20 -------------- 49x = 61
you'll need to check the calculations
So x=(61/49)?
the unlucky thing about the question you posted is that the answers are all ugly fractions... but I hope it helps you should be able to get x then substitute it into either equation 4 or 5 to find y then substitute the values of x and y into any of the original equations to find x hope it makes sense
that's x... very ugly
Huh. The answer is x=1, y=3, z=2...
well you need to check the equations 1st seems ok... 5 - 3 + 2 = 4 2nd 1 + 6 - 2 = 5 3rd 2 + 9 + 6 = 17 you have 5 can you check the 3rd equation in the repost....
so it looks like the last equation should be 2x + 3y - 3z = 5
Yes. Oops!! So sorry
ok... so equation 4 is fine... now multiply equation 1 by 3 and then add equation 3\\ 15x - 3y + 3z = 12 2x + 3y + 3z = 5 ------------------ 17x = 17 so now that makes sense... find x, substitute it into equation 4 to find y then substitute the values into any of the original equations to find z hope it now makes sense.
oops should read -3z = 5
yes!! thank you so much!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question