Systems of Equations, please help =)
Solve without matrix
5x-y+z=4; x+2y-2=5; 2x+3y-3=5
I have the answer, but have tried multiple times and cannot get to it.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
WAIT that's the wrong equation!!
5x-y+Z=4, x+2y-Z=5, 2x+3y+3Z=5
so which letter do you want to eliminate... y or z..?
Not the answer you are looking for? Search for more explanations.
ok... so we'll eliminate z you'll end up with 2 equations in 2 unknowns
so add equations 1 and 2
5x -y + z = 4
x + 2y - z = 5
6x + y = 9 equation 4
now multiply equation 2 by 3 and add equation 3
3x + 6y -3z = 15
2x + 3y + 3z = 5
5x + 9y = 20 equation 5
easiest thing to do now is to multiply equation 4 by 9 and subtract equation 5 which will eliminate y
54x + 9y = 81
- 5x - 9y = -20
49x = 61
you'll need to check the calculations
the unlucky thing about the question you posted is that the answers are all ugly fractions...
but I hope it helps
you should be able to get x
then substitute it into either equation 4 or 5 to find y
then substitute the values of x and y into any of the original equations to find x
hope it makes sense
that's x... very ugly
Huh. The answer is x=1, y=3, z=2...
well you need to check the equations
1st seems ok... 5 - 3 + 2 = 4
2nd 1 + 6 - 2 = 5
3rd 2 + 9 + 6 = 17 you have 5
can you check the 3rd equation in the repost....
so it looks like the last equation should be
2x + 3y - 3z = 5
Yes. Oops!! So sorry
ok... so equation 4 is fine...
now multiply equation 1 by 3 and then add equation 3\\
15x - 3y + 3z = 12
2x + 3y + 3z = 5
17x = 17
so now that makes sense...
find x, substitute it into equation 4 to find y
then substitute the values into any of the original equations to find z
hope it now makes sense.