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Implicit? :o Oo neato

So whatchu think?
Set up that product rule, ya?

so cosx=tany+sec^2(dy/dx) ya?

Oh! I had it written down but forgot to type it here.

\[\large\rm \frac{d}{dx}(1+\tan y)=?\]

the 1 would become 0 and the tan y would be sec^2 (y) (dy/dx), is that right?

\[\large\rm \frac{d}{dx}(1+\tan y)=0+\sec^2(y)y'\]Ok great!

\[\large\rm \cos x=1+\tan y+xy' \sec^2 y\]So how do we do that? :)
Any ideas?

you lost me. did you just move the y' to the x in front of sec^2(y)?

before you did that I could isolate y' and get (cosx-tany-1)/(x(sec^2)y) on the other side

We did a lot like that in class

Is there something wrong with that?

I'm not sure what (sec^2)y is.
Careful with the way you do your brackets :)

written down it looks identical to yours

i'm just not too good at getting this stuff typed

oh i see :D

Refer to the attachment using Mathematica v9