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anonymous
 one year ago
I tried getting help in the engineering section, but no one's around to help, apparently, so I'll just copy/paste my question here.
I've gotten about halfway through this one question and I'm a little confused as to what to do next. Is there anyone out there who can help me? The question is thus; "The motion of a particle is defined by the equations and x=(2t+t2)m and y=(t2)m, where t is in seconds. Find v_n, v_t, a_n and a_t where (t=2) seconds."
anonymous
 one year ago
I tried getting help in the engineering section, but no one's around to help, apparently, so I'll just copy/paste my question here. I've gotten about halfway through this one question and I'm a little confused as to what to do next. Is there anyone out there who can help me? The question is thus; "The motion of a particle is defined by the equations and x=(2t+t2)m and y=(t2)m, where t is in seconds. Find v_n, v_t, a_n and a_t where (t=2) seconds."

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've already found v_n and v_t, I want to know how to obtain a_n and a_t. I know the general equation for polar acceleration, but it doesn't seem to be all that applicable here. So I've been working on this problem for awhile. Just to prove that I'm not trying to be lazy, I'll explain how I found v_n and v_t. The definition of velocity is that it is tangent to the position curve. Theregore, there can BE no normal velocity vector. Thus, v_n = 0. As for v_t, that is just velocity times the unit tangent vector. To find this, I derive the x and y components of the position vector, and then plug in the value t= 2, from which I then calculate the magnitude of the velocity. This gets me v_t = 7.21 m/s.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I figured I could try the physics section here since this Dynamics problem is essentially based on kinematics, anyway.
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