Need Help! Its a combination problem.5

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Need Help! Its a combination problem.5

Mathematics
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I don't think your factorial equation is right... follow this format \[\frac{ n! }{ k! (n-k)! }\] and try simplifying now
15! / 15! (5-15)!
On my notes it says nCk = n!/(n-k)! k! so id rather do it that way :) but it would still be the same way right?

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Other answers:

Wait actually
I wrote the wrong number.. I just need to figure out how to simplify 15C5
its supposed to be 3003 but idk how? I can do it from a calculator, but on a quiz i need to be able to show my work
You would get 15!/ 15!. -10! that way and I don't think you should have a negative factorial
I got 15!/10! 5!
yup thats right
|dw:1442908599294:dw|
The way i simplified it was 15 14 13 12 11 10 _________________________ 10 5 4 3 2 1 I crossed out the 10's and then from there it doesnt seem right, but its the way my teacher taught us. so for ex, 5 *3 = 15 7*2 = 14
so then 3 would go on top of the 15 and the 7 would go on top of the 14
yeah I did the same, then you can cancel a few other things out as well
yup seems right so far
thats where im stuck because i cant get 3003 if i do then it would be 3 * 7 * 11 *13 but what happens to the 12?
so answer is 3003 right?
yes
okay so you have \[\frac{ 15 . 14. 13. 12. 11 }{ 5. 4. 3. 2. 1}\]
yes
|dw:1442908920946:dw|
do you follow what I did there?
is that a 4?
above the 12?
yea
okay yeah i understand so far
and it cancels with the 4 below
yup so now we have left 3 x 7 x 13 x 11
OHH LOL OKAY I GET IT NOW ! AHHHH okay i was doing it right then
yup you were right all along ahahahha :D
wait what happend to the 3? Lol
the bottom one got cancelled to make the 12 on top into a 4
ooookay yay! thanks :)
haha no problem :)

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