## steve816 one year ago Determine whether this function is even or odd

1. steve816

$h(x)=\frac{ -x^3 }{ 3x^2-9 }$

2. FireKat97

Use these two rules- if h(x) = h(-x) the function is considered even. if -h(x) = h(-x) the function is considered odd.

3. steve816

I plugged in -x and got neither. Is that right?

4. FireKat97

so what exactly did you get when you plugged in -x?

5. steve816

$h(x)=\frac{ x^3 }{ 3x^2-9 }$

6. FireKat97

okay and now try and find the function -h(x)

7. steve816

$h(x)=\frac{ -x^3 }{ -3x^2+9 }$

8. FireKat97

No, when you multiply by a negative, you don't have to multiply both the numerator and denominator by the negative. So in this case, you should get $-\frac{ -x^3 }{ 3x^2 -9}$ and the two negatives should cancel so you get left with $\frac{ x^3 }{ 3x^2-9 }$

9. FireKat97

now that you have found h(x) and -h(x) what do you notice

10. steve816

oooooh silly mistake, so it is ODD!

11. FireKat97

yup :D

12. steve816

THanks for the help

13. FireKat97

no problem

14. ytrewqmiswi

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