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Hitaro9
 one year ago
Does the Series ke^k^2 converge or diverge?
Hitaro9
 one year ago
Does the Series ke^k^2 converge or diverge?

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hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{k=1}^{infinity}k e^{k ^{2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0$$\large \sum_{k=1}^{\infty}k e^{k ^{2}}= $$ notice that is close to the derivative of \( \large e^{x^2} \)

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0Oh, right, there's a thing in the book about an integral test. We haven't discussed it in class yet, but, I'm guessing that's what this is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sort of, I was thinking of this http://prntscr.com/8j57eg

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0That looks significantly more complicated than what we've been doing thus far.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but now that you mention it, you can use integral test

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0Okay then, that's good. I'm reading up on it now, might ask some questions

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2applied the ratio test yet?

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0Ratio test didn't seem to work, unless I made some algebraic errors

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2\[\large \frac{(k+1) e^{(k+1) ^{2} }}{k e^{k ^{2}}}=\]

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0Right, then I ended up with some mess with the exponents that didn't seem to work out nicely

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2\[\large \frac{k+1}{k} e^{(2k+1)}\]

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0To save you the work of typing out a whole bunch of equations, if there's some way to do it with the ratios, I should be able to handle it if you can help me through the algebra

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0Umm one moment. That's not what I did so that's probably where I went wrong

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2expand the top exponent and subtract the bottom one

hitaro9
 one year ago
Best ResponseYou've already chosen the best response.0Right that makes sense. I dunno why I didn't see that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because the e^(2k+1) is in the denominator. nice work irishboy
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