pinklion23
  • pinklion23
@FireKat97 same thing https://static.k12.com/bank_packages/files/media/mathml_4e006c004e36a66062713acfcc905e2f20ed519b_1.gif
Mathematics
schrodinger
  • schrodinger
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pinklion23
  • pinklion23
A.one solution B.infinite solutions C.no solution
FireKat97
  • FireKat97
okay so try opening the brackets on the right hand side this time
FireKat97
  • FireKat97
and show me what you get

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pinklion23
  • pinklion23
i get 9a right?
FireKat97
  • FireKat97
on the right hand side... \[\frac{ 1 }{ 3 } (9a -18)\] so to simplify this, we would do... \[\frac{ 1 }{ 3 } . 9a - \frac{ 1 }{ 3 } . 18\] thats how we open a bracket, so we multiply the term outside to both the inside terms, so can you please simplify this?
pinklion23
  • pinklion23
ok ok i will
pinklion23
  • pinklion23
1/3*9a-5.94
pinklion23
  • pinklion23
1/3*306a?
FireKat97
  • FireKat97
not quite, if you multiply the above equation out, you should get 3a - 6 for the night hand side, do you see why? all I've done here is expand \[\frac{ 1 }{ 3 }9a - \frac{ 1 }{ 3 }18\]
pinklion23
  • pinklion23
im sorry i am not awake this morning i fully understand ):0
FireKat97
  • FireKat97
hahaha no problem, we all have those mornings
pinklion23
  • pinklion23
usterday i was on the ball but today i am have like 1000000 brain farts :P
FireKat97
  • FireKat97
hahaha dw thats me most days, totally brain dead
pinklion23
  • pinklion23
so the answer is A right because a= 2
FireKat97
  • FireKat97
umm not quite, but it is A
pinklion23
  • pinklion23
oh but what does a= then because 6/3=2....
FireKat97
  • FireKat97
wait where did you get 6/3 from?
FireKat97
  • FireKat97
remember we have to let the left hand side equal to our simplifies right hand side and then solve
FireKat97
  • FireKat97
simplified*
pinklion23
  • pinklion23
3a-6 right then what do i do?
FireKat97
  • FireKat97
so now we go back to our original equation where we had \[6 - a = \frac{ 1 }{ 3 } (9a -18)\] except, we've already simplified the rightt hand side above so its just... \[6 - a = 3a -6\]
FireKat97
  • FireKat97
Now we can solve for a
pinklion23
  • pinklion23
yeah then a=0
pinklion23
  • pinklion23
ahhhhhhh im dead >:(
pinklion23
  • pinklion23
im so mad with my self right now >I0
FireKat97
  • FireKat97
um, not exactly, you would take the -a from the left hand side over to the right so you get 6 = 3a + a -6
FireKat97
  • FireKat97
and do the same thing with the 6 on the right hand side, you want to take that over to the left
FireKat97
  • FireKat97
collect like terms to simplify
pinklion23
  • pinklion23
oh ok hey you should become a qualified helper your great :)
FireKat97
  • FireKat97
hahaha tbh I don't think so, Im still pretty new to this xD but thanks anyway :)
FireKat97
  • FireKat97
But do you understand it all now?
pinklion23
  • pinklion23
wait i got this bro hold on
pinklion23
  • pinklion23
a = 3 ha is that right?
FireKat97
  • FireKat97
yupppp thats correct :D
pinklion23
  • pinklion23
YES!!!!!!!!!!!!!!! i need help with another pls X)
FireKat97
  • FireKat97
sure thing

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