Simplify

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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simplify what
Hold on im getting it
Simplify cube root of 7 over fifth root of 7. 7 to the power of 1 over 5 7 to the power of 8 over 15 7 to the power of 5 over 3 7 to the power of 2 over 15

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How do I simplify ??
im only in 6th grade :( i cant do all that
Ohh, okay.
Do you know how to turn the radicals into exponents?
No :(
Use this rule\[\sqrt[n]{a}=a^{\frac{ 1 }{ n }}\] So you can change your numerator to \[7^\frac{ 1 }{ 3 }\] What would the denominator be?
I dont get it
|dw:1442935986567:dw|
does that make sense?
Kind of.. I still dont get it. Nvm ill just guess on it cuz I have to hurry and get this test done before 12. Thanks though!
what is up with the drawing it makes no sense
what about it doesn't make sense?
Well, it does make sense I just dont how to do it when theres a fraction of the radical things
You have to take the small number from the radical and write it as an exponent.\[\frac{ \sqrt[3]{7} }{ \sqrt[5]{7} }=\frac{ 7^{\frac{ 1 }{ 3 }} }{ 7^{\frac{ 1 }{ 5 }} }=7^{(\frac{ 1 }{ 3 }-\frac{ 1 }{ 5 })}\]
So is the answer a?
no. subtract 1/3 - 1/5 to get the final exponent
idk. Ugh forget it

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