anonymous
  • anonymous
Simplify
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
simplify what
anonymous
  • anonymous
Hold on im getting it
anonymous
  • anonymous
Simplify cube root of 7 over fifth root of 7. 7 to the power of 1 over 5 7 to the power of 8 over 15 7 to the power of 5 over 3 7 to the power of 2 over 15

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anonymous
  • anonymous
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anonymous
  • anonymous
How do I simplify ??
anonymous
  • anonymous
im only in 6th grade :( i cant do all that
anonymous
  • anonymous
Ohh, okay.
anonymous
  • anonymous
@welshfella help
anonymous
  • anonymous
Do you know how to turn the radicals into exponents?
anonymous
  • anonymous
No :(
anonymous
  • anonymous
Use this rule\[\sqrt[n]{a}=a^{\frac{ 1 }{ n }}\] So you can change your numerator to \[7^\frac{ 1 }{ 3 }\] What would the denominator be?
anonymous
  • anonymous
I dont get it
anonymous
  • anonymous
|dw:1442935986567:dw|
anonymous
  • anonymous
does that make sense?
anonymous
  • anonymous
Kind of.. I still dont get it. Nvm ill just guess on it cuz I have to hurry and get this test done before 12. Thanks though!
anonymous
  • anonymous
what is up with the drawing it makes no sense
anonymous
  • anonymous
what about it doesn't make sense?
anonymous
  • anonymous
Well, it does make sense I just dont how to do it when theres a fraction of the radical things
anonymous
  • anonymous
You have to take the small number from the radical and write it as an exponent.\[\frac{ \sqrt[3]{7} }{ \sqrt[5]{7} }=\frac{ 7^{\frac{ 1 }{ 3 }} }{ 7^{\frac{ 1 }{ 5 }} }=7^{(\frac{ 1 }{ 3 }-\frac{ 1 }{ 5 })}\]
anonymous
  • anonymous
So is the answer a?
anonymous
  • anonymous
@peachpi
anonymous
  • anonymous
no. subtract 1/3 - 1/5 to get the final exponent
anonymous
  • anonymous
idk. Ugh forget it

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