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baru
 one year ago
from the "advanced example" in the lecture clip on lagrange multipliers. Why are u1, u2 and u3 perpendicular to the sides of the base triangle??
http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/2.partialderivatives/partclagrangemultipliersandconstraineddifferentials/session41advancedexample/
baru
 one year ago
from the "advanced example" in the lecture clip on lagrange multipliers. Why are u1, u2 and u3 perpendicular to the sides of the base triangle?? http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/2.partialderivatives/partclagrangemultipliersandconstraineddifferentials/session41advancedexample/

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phi
 one year ago
Best ResponseYou've already chosen the best response.1I guess it is hard to visualize. But consider the "slant height" of a face from point P down to its base leg. That slant height makes a 90 degree angle with the leg dw:1442951690471:dw now rotate that slant height until it lies in the xy plane dw:1442951759766:dw it will remain 90 degrees to the leg Also, point P when projected down to the xy plane will lie on this rotated "slant height" Thus we have (looking down on the base) dw:1442951912332:dw

baru
 one year ago
Best ResponseYou've already chosen the best response.1yep... got it!! you mean to say that the "slant height" and the "projected slant height" both lie on the plane perpendicular to the base leg right?

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, that is good way to describe it.
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