anonymous
  • anonymous
Rewrite in simplest radical form x^5/6 divided by x^1/6
Mathematics
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anonymous
  • anonymous
Rewrite in simplest radical form x^5/6 divided by x^1/6
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Nnesha
  • Nnesha
when we divide same base , `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]
anonymous
  • anonymous
Do you subtract both the bottom number and the top number or just the top one?
Nnesha
  • Nnesha
just subtract their exponents top exponent `minus` bottom exponents base would stay the same

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anonymous
  • anonymous
.67
Nnesha
  • Nnesha
hmm we need to write it in radical form so keep the fraction
anonymous
  • anonymous
How?
Nnesha
  • Nnesha
how did you get .67 ??
Nnesha
  • Nnesha
i mean what did you subtract to get .67 what did you type into the calculator ?
anonymous
  • anonymous
I subtract 5/6 from 1/6
Nnesha
  • Nnesha
yes so \[\huge\rm \frac{ 5 }{ 6 }-\frac{ 1 }{ 6 }\] what's the common denominator ?
anonymous
  • anonymous
6
anonymous
  • anonymous
x^4/6?
Nnesha
  • Nnesha
yes right so since the denominator of both fraction are the same \[\frac{ 5-1 }{ 6 }\] so you can just subtract the numbers in the numerator
Nnesha
  • Nnesha
yes right reduce the fraction
anonymous
  • anonymous
x^2/3?
Nnesha
  • Nnesha
yes right now apply the exponent rule to convert into radical form \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n}\]
anonymous
  • anonymous
\[\sqrt[3]{x ^{2}}\]
Nnesha
  • Nnesha
looks good

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