paul10175
  • paul10175
ex − 12e−x − 1 = 0 solve to 4 decimal places. please
Mathematics
jamiebookeater
  • jamiebookeater
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paul10175
  • paul10175
the x values are exponents
anonymous
  • anonymous
this? \[e^x-12e^{-x}-1=0\]
paul10175
  • paul10175
yes peachpi

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anonymous
  • anonymous
Multiply through by \(e^x\). \(e^{2x}-12-e^x=0\) rearrange and factor \(e^{2x}-e^x-12=0\) \((e^x-4)(e^x+3)=0\)
paul10175
  • paul10175
hell yea that was right. I just solved for x, but e^x+3 is not in the domain

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